Answer:
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Step-by-step explanation:
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Answer:the third option is correct
Step-by-step explanation:
The system of equations are
y = 2x^2 - 5x - 7 - - - - - - - - - - -1
y = 2x + 2 - - - - - - - - - - - - - 2
We would equate equation 1 and equation 2. It becomes
2x^2 - 5x - 7 = 2x + 2
2x^2 - 5x - 2x - 7 - 2 = 0
2x^2 - 7x - 9 = 0
We would find two numbers such that their sum or difference is -7x and their product is - 18x^2. The two numbers are 2x and - 9x. Therefore
2x^2 + 2x - 9x - 9 = 0
2x(x + 1) - 9(x + 1) = 0
2x - 9 = 0 or x + 1 = 0
2x = 9 or x = - 1
x = 9/2 = 4.5
Substituting x = 4.5 or x = -1 into equation 2, it becomes
y = 2 × 4.5 + 2 or y = 2 × - 1 + 2
y = 11 or y = 0
Therefore, the solutions are
(4.5, 11) (- 1, 0)
Quadratic function whose zeros are 5 and -7 is x^2+2x-35=0
Step-by-step explanation:
Write a quadratic function h whose zeros are 5 and -7
If 5 and -7 are zeros of quadratic function then:
x=5 and x=-7
or x-5 = 0 and x+7=0
So, Finding quadratic equation:
So, quadratic function whose zeros are 5 and -7 is x^2+2x-35=0
Keywords: Quadratic Function
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