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Leokris [45]
2 years ago
7

Many who move to business-oriented information security were formerly__________ who were often involved in national security or

cybersecurity .
Computers and Technology
1 answer:
kirill [66]2 years ago
5 0

Answer:

The information security function

Explanation:

Many who move to business-oriented information security were formerly_____ who were often involved in national security or cybersecurity . All of the above The information security function

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A piece of glass has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavele
kobusy [5.1K]

Answer:

200 nm

Explanation:

We need a constructive interference to see the bright reflection

we know that 2t=m\lambda  where m=1 and \lambda is the wavelength of the gasoline

so \lambda =\frac{560}{1.4}=400nm

putting the value of m and \lambda in thickness equation

t=\frac{1\times 400}{2}=200nm

so the thickness of the film will be 200 nm

3 0
3 years ago
Darian is preparing for a presentation about the poor condition of the locker rooms at school. Match each of the key components
Gemiola [76]

Answer:

Purpose - To paurswade the board to change the conditions of the locker room

Topic - Locker room condition

Method - Electronic Slideshow

Audience - School Board

7 0
2 years ago
Black and white squares codehs, i need the whole code (40 points for correct answer)
ludmilkaskok [199]

Answer:

speed(0)

penup()

setposition(-100,0)

count=0

def make_squares(i):

if i % 2 == 0:

begin_fill()

for i in range(4):

forward(25);

left(90)

end_fill()

penup()

pendown()

for i in range(6):

pendown()

make_squares(i)

penup()

forward(35)

Explanation:

3 0
2 years ago
Read 2 more answers
We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is
bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons  to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons  to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons  to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as  one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons  to find the middle terms.

If list has 18 elements, there are two middle terms as  one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons  to find the middle terms.

If list has 20 elements, there are two middle terms as  one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons  to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0
3 years ago
What is extraction, transformation, and loading? Group of answer choices It is a process of entering data, tracking data, and lo
Tcecarenko [31]

Answer:

It is a process that extracts information from internal and external databases, transforms it using a common set of enterprise definitions, and loads it into a data warehouse.

Explanation:

Extraction, transformation, and loading can be defined as a process that extracts information from internal and external databases, transforms it using a common set of enterprise definitions, and loads it into a data warehouse.

A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to create, store, modify, retrieve and manage data or informations in a database. Generally, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.

A data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.

In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.

This ultimately implies that, a data dictionary found in a computer database system typically contains the records about all the data elements (objects) such as data relationships with other elements, ownership, type, size, primary keys etc. This records are stored and communicated to other data when required or needed.

7 0
2 years ago
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