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3 years ago

7

NEED HELP ON 13 AND 14 ITS OK IF YOU CAN ONLY ANSWER ONE, I WILL GIVE OUT BRAINLIEST, FIND THE LENGTH OF THE SEGMENTS IN THE PIC

TURE PLEASE

1 answer:

marissa [1.9K]3 years ago

6 0

Answer:

It is the string theory dialated from quantum physics and decierived to the injudices of quadratic equations.

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9. The ratio of boys to girls in a class is 4:5. How

lisabon 2012 [21]

A.30
24 divided by 6 is for
5 times 6 is 30

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3 years ago

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9999 + 9999 = ?????????????????????

kap26 [50]

Answer:

The answer will be 19998

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3 years ago

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Suppose that E and F are two events and that P(E)=.8 and P(F/E)=.6 What is P(E and F)?

jeka57 [31]

Lets turn E into x and F into y.

We already know that x is 0.8. And if y/x = 0.6, we have to figure that out.

y/x = 0.6

y/0.8 = 0.6

Multiply by 8 to get y = 0.48.

So we have to find P(xy)

So if we know that x = 0.8 and y = 0.48 then all we have to do is multiply 0.48 and 0.8.

0.48 * 0.8 = 0.384

P(E and F) is 0.384.

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4 0

4 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is

$A'=2\pi r^2 + \pi r^2 = 3 \pi r^2$

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

$\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r$

6 0

3 years ago

Hi. I need help with these questions.<br> See image for question.<br> Answer 14 and 13

irinina [24]

Answer:

13) 36x² + 9x - 4 = 0

14) 21x² + 20x + 100 = 0

Step-by-step explanation:

13.

<h3>Given</h3>

<u>Quadratic equation</u>

4x² - 3x - 4 = 0
With the roots of α and β

<h3>To Find </h3>

The quadratic equation with roots of 1/(3α) and 1/(3β)

<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

α + β = -b/a ⇒ α + β = -(-3)/4 = 3/4
αβ = c/a ⇒ αβ = -4/4 = - 1

<u>New equation is:</u>

(x - 1/(3α))(x - 1/(3β)) = 0
x² - (1/(3α) + 1/(3αβ))x + 1/(3α3β) = 0
x² - ((3α + 3 β)/(3α3β))x + 1/(3α3β) = 0
x² - ((α + β)/(3αβ))x + 1/(9αβ) = 0
x² - (3/4)/(3(-1))x + 1/(9(-1)) = 0
x² + 1/4x - 1/9 = 0
36x² + 9x - 4 = 0

===================

14.

<h3>Given</h3>

<u>Quadratic equation</u>

3x² +2x + 7 = 0
With the roots of α and β

<h3>To Find </h3>

The quadratic equation with roots of α + 1/β and β + 1/α

<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

α + β = -b/a ⇒ α + β = -2/3
αβ = c/a ⇒ αβ = 7/3

<u>New equation is:</u>

(x - (α + 1/β))(x - (β + 1/α)) = 0
x² - (α + 1/β + β + 1/α)x + (α + 1/β) (β + 1/α) = 0
x² - (α + β + (α + β)/αβ )x + αβ + 1/αβ + 2 = 0
x² - (-2/3 - (2/3)/(7/3))x + 7/3 + 1/(7/3) + 2 = 0
x² - (-2/3 - 2/7)x + 7/3 + 3/7 + 2 = 0
x² + (14 + 6)/21x + (49 + 9 + 42/21) = 0
x² + 20/21x + 100/21 = 0
21x² + 20x + 100 = 0

8 0

3 years ago