Answer:
3.1415926535 8979323846
Step-by-step explanation:
Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
Answer:
option D
Step-by-step explanation:
Jerry solved this equation:

In the first step , she multiplied 3 inside the parenthesis
1. 
In step 2, 3/4 is added on both sides
2. 
In step 3, we take LCD 12
3. 
In step 4, add the fractions
4. 
Here, 3 or 3/1 are same.

In step 5, to remove 3/1 we multiply both sides by 1/3.
Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1


In step 5, he should have multiplied both sides by 1/3
Answer:
40
Step-by-step explanation: