Xy = 8
x + y = 6
x + y = 6
x - x + y = -x + 6
y = -x + 6
xy = 8
x(-x + 6) = 8
x(-x) + x(6) = 8
-x² + 6x = 8
-x² + 6x - 8 = 0
-1(x²) - 1(-6x) - 1(8) = 0
-1(x² - 6x + 8) = 0
-1 -1
x² - 6x + 8 = 0
x² - 4x - 2x + 8 = 0
x(x) - x(4) - 2(x) + 2(4) = 0
x(x - 4) - 2(x - 4) = 0
(x - 2)(x - 4) = 0
x - 2 = 0 or x - 4 = 0
+ 2 + 2 + 4 + 4
x = 2 or x = 4
x + y = 6
2 + y = 6
- 2 - 2
y = 4
(x, y) = (2, 4)
or
x + y = 6
4 + y = 6
- 4 - 4
y = 2
(x, y) = (4, 2)
The two numbers that add up to 6 and multiply to 8 are 4 and 2.
39 depending on the prices but 39 is how many he sold
Answer:
Step-by-step explanation:
The reason you haven't gotten an answer to this is because in its current formatting, there is no answer. Here's what I mean:
The first equation is going to be concerning the NUMBER of memberships sold, where m is male and f is female. The total number of memberships was 10:
m + f = 10
Now for the money equation. The total amount of money made from that number of memberships was 3000, where male memberships cost $300 and so do the female memberships, giving us an equation of
300m + 300f = 3000
Go back to the first equation and solve for either m or f. I solved for m in terms of f:
m = 10 - f and sub that into the second equation for m to get:
300(10 - f) + 300f = 3000 and
3000 - 300f + 300f = 3000. Here is where you find the problem. The -300f and the 300f cancel each other out, leaving you with the fact that
3000 = 3000 which it does, but it doesn't give us any viable answer.
I would have to say that since we can't do math on this, that the most credible answer you'll find is that the same number of male and female memberships were sold because 5 male memberships cost $1500 (5 memberships at $300 a piece is $1500) and 5 female memberships also cost $1500.
1500 + 1500 = 3000
Answer:
packs
Step-by-step explanation:
Given
Required
The total packs bought
This is calculated as:
Answer:
31.52% increase (decrease)
Step-by-step explanation:
To find the decrease in the percentage of students from the previous year to the current year, you must establish a baseline to be your maximum (100%). For this we'll use the 92 students. From here, we need the current 63 students to establish the current percentage.
Simply:
63/92 == .6848 == 68.48%
So our current percentage of students is 68.48%. We want the decrease of the students compared to the previous percentage so we'll need to do the maximum minus the current to get the change (or the decrease).
100% - 68.48% = 31.52%
Thus, the population increase (decrease) for this year is 31.52%.
