Find the surface area of the pyramid. The side lengths of the base are equal. pls help D:
1 answer:
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<h2>Answer:</h2>
A. It is a many-to-one function.
<h2>Step-by-step explanation:</h2>Hello! It will be a pleasure to help to figure out what's the correct answer to this problem. First of all, we have the following function:
When plotting this function, we get the red graph of the function shown below. So let's solve this as follows:
<h3>A. It is a many-to-one function.</h3>True
A function is said to be many-to-one there are values of the dependent variable (y-values) that corresponds to more than one value of the independent variable (x-values). To test this, we need to use the Horizontal Line Test. So let's take the horizontal line , and you can see from the first figure below that
is mapped onto
. so this is a many-to-one function.
Since this is a many-to-one function, it can't be a one-to-one function.
<h3>C. It is not a function.</h3>False
Indeed, this is a function
<h3>D. It fails the vertical line test.</h3>False
It passes the vertical line test because any vertical line can intersect the graph of the function at most once. An example of this is shown in the second figure below.
Answer:
unreadable score = 35
Step-by-step explanation:
We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".
There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":
1) The mean score of ALL exams (including the unreadable one) is 80
so the equation to represent this statement is:
mean of ALL exams = 80
By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:
since the mean is the addition of all values divided the total number of exams.
in a similar way we can write what the mean of just the readable exams is:
(notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.
Based on the equation above, we can find what "R" is by multiplying both sides by 9:
Therefore we can now use this value of R in the very first equation we created, and solve for "x":