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Tems11 [23]
3 years ago
11

Help me now asap please !!!!!!!!!!!

Mathematics
2 answers:
Wewaii [24]3 years ago
8 0

<em>answer =50.24 {yd}^{2}   \\ solution \\ diameter = 8 \: yards \\ radius =  \frac{8}{2}  = 4 \: yards \\ area \: of \: circle = \pi \:  {r}^{2}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \: 3.14 \times  {4}^{2}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 3.14 \times 16 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 50.24 \:  {yd}^{2}  \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

7nadin3 [17]3 years ago
3 0

Answer:

50.24 yd^2

Step-by-step explanation:

Find the radius from the diameter given.

r=d/2

r=8/2

r=4

Use the area of circle formula.

\pi r^2

3.14 \times 4^2

16 \times 3.14

=50.24

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Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
3 years ago
Find the​ p-value for the indicated hypothesis test with the given standardized test​ statistic, z. decide whether to reject upp
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8 0
3 years ago
What would the equation be for d=0.68t + 1.5
frozen [14]

Answer:

Step-by-step explanation:

a)

d=0.68t + 1.5        if t time is 3 hrs

d=0.68(3) + 1.5

 = 2.04 + 1.5

d= 3.54 ft

b)

d=0.68t + 1.5     if d depth is 4 ft    solve for t

d - 1.5 = 0.68t

(d - 1.5) / 0.68 = t

(4 - 1.5) / 0.68 = t

t = 2.5/0.68

t  =  3.68 ft

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7 0
3 years ago
Solve the system of equations -x - 2y = 11 and -3x - 2y = -7
rjkz [21]
Answer: (9,-10) or x=9...y=-10
4 0
3 years ago
What is 44/3 as a whole or mixed number in simplest form.
Kay [80]

\dfrac{44}{3}=\dfrac{42+2}{3}=\dfrac{42}{3}+\dfrac{2}{3}=14+\dfrac{2}{3}=14\dfrac{2}{3}


you can use long division with Remainder (look at the picture).

\dfrac{44}{3}=44:3=14\ + R(2)=14\dfrac{2}{3}

8 0
3 years ago
Read 2 more answers
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