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1 year ago

Solve 4+3(x-2)=2x-4.

Mathematics

2 answers:

AnnyKZ [126]1 year ago

8 0

Answer:

-2

Step-by-step explanation:

4+3(x-2)=2x-4

distibute 3 to (x-2)

4+3x-6=2x-4

simplify

3x-2=2x-4

add -4 (becomes +4) to -2

3x+2=2x

subtract 3x

2=-x

divide the negative

-2=x

alukav5142 [94]1 year ago

4 0

Answer:

x=-2

Step-by-step explanation:

isolate the variable and the numbers

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193 is what percent of 256? Round to the nearest thousandth.

jenyasd209 [6]

Answer:

75.391

Step-by-step explanation:

193x100/256=75.391

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2 years ago

Angle P is an acute angle.

TEA [102]

A acute angle is always less than 90 degrees. So the answer is A.

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3 years ago

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

For the given function, x can have what value?

Lyrx [107]

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

5 0

2 years ago

What is the answer to 6 1/6 - 3 5/6 =

antoniya [11.8K]

6 1/6 - 3 5/6= 2 1/3
Hope this Helps:D
Have a great rest of a brainly day!

7 0

2 years ago