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Kaylis [27]
2 years ago
8

Answers please this is very hard :))

Mathematics
2 answers:
snow_lady [41]2 years ago
8 0

Answer:

1. you dont add before you multiply

2 they didnt do the parenthesis first...which was their mistake

Step-by-step explanation:

Ber [7]2 years ago
6 0
PEMDAS that should help lol
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1.905 rounded to the nearest tenth is 1.9
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WILL GIVE BRAINLIEST Mr. and Mrs. Bailey hope to send their son to college in eleven years. How much money should they invest no
Ronch [10]

Mr. and Mrs. Bailey need to invest $2906.50 so as to send their son to college.

<h3>Compound interest</h3>

Compound interest is given by:

A=P(1+\frac{r}{n})^{nt}

where A is the amount after t years, P is initial amount, r is the rate and n is the times compounded per period

Given that n = 1, r = 9% = 0.09, A = $7500 t = 11. Hence:

7500=P(1+\frac{0.09}{1} )^{1*11}\\\\P=\$2906.50

Mr. and Mrs. Bailey need to invest $2906.50 so as to send their son to college.

Find out more on Compound interest at: brainly.com/question/24924853

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What is the supplementary angel of 60
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11. Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is F(x) 5 5 0 x , 0
NISA [10]

Question not properly presented

Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is F(x)

0 ------ x<0

x²/25 ---- 0 ≤ x ≤ 5

1 ----- 5 ≤ x

Use the cdf to obtain the following.

(a) Calculate P(X ≤ 4).

(b) Calculate P(3.5 ≤ X ≤ 4).

(c) Calculate P(X > 4.5)

(d) What is the median checkout duration, μ?

e. Obtain the density function f (x).

f. Calculate E(X).

Answer:

a. P(X ≤ 4) = 16/25

b. P(3.5 ≤ X ≤ 4) = 3.75/25

c. P(4.5 ≤ X ≤ 5) = 4.75/25

d. μ = 3.5

e. f(x) = 2x/25 for 0≤x≤2/5

f. E(x) = 16/9375

Step-by-step explanation:

a. Calculate P(X ≤ 4).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(X ≤ 4) = F(x) {0,4}

P(X ≤ 4) = x²/25 {0,4}

P(X ≤ 4) = 4²/25

P(X ≤ 4) = 16/25

b. Calculate P(3.5 ≤ X ≤ 4).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(3.5 ≤ X ≤ 4) = F(x) {3.5,4}

P(3.5 ≤ X ≤ 4) = x²/25 {3.5,4}

P(3.5 ≤ X ≤ 4) = 4²/25 - 3.5²/25

P(3.5 ≤ X ≤ 4) = 16/25 - 12.25/25

P(3.5 ≤ X ≤ 4) = 3.75/25

(c) Calculate P(X > 4.5).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(4.5 ≤ X ≤ 5) = F(x) {4.5,5}

P(4.5 ≤ X ≤ 5) = x²/25 {4.5,5}

P(4.5 ≤ X ≤ 5)) = 5²/25 - 4.5²/25

P(4.5 ≤ X ≤ 5) = 25/25 - 20.25/25

P(4.5 ≤ X ≤ 5) = 4.75/25

(d) What is the median checkout duration, μ?

Median is calculated as follows;

∫f(x) dx {-∝,μ} = ½

This implies

F(x) {-∝,μ} = ½

where F(x) = x²/25 for 0 ≤ x ≤ 5

F(x) {-∝,μ} = ½ becomes

x²/25 {0,μ} = ½

μ² = ½ * 25

μ² = 12.5

μ = √12.5

μ = 3.5

e. Calculating density function f (x).

If F(x) = ∫f(x) dx

Then f(x) = d/dx (F(x))

where F(x) = x²/25 for 0 ≤ x ≤ 5

f(x) = d/dx(x²/25)

f(x) = 2x/25

When

F(x) = 0, f(x) = 2(0)/25 = 0

When

F(x) = 5, f(x) = 2(5)/25 = 2/5

f(x) = 2x/25 for 0≤x≤2/5

f. Calculating E(X).

E(x) = ∫xf(x) dx, 0,2/5

E(x) = ∫x * 2x/25 dx, 0,2/5

E(x) = 2∫x ²/25 dx, 0,2/5

E(x) = 2x³/75 , 0,2/5

E(x) = 2(2/5)³/75

E(x) = 16/9375

4 0
3 years ago
A cylinder has a radius of 3 cm. Sand is poured into the cylinder to form a layer 2 cm deep. What is the volume of sand in the c
netineya [11]

Answer:

Volume=56.54cm³

Step-by-step explanation:

Solution,\\\\Radius(r)=3cm\\\\Height(h)=2cm\\\\Now,\\\\Volume=\pi r^{2} h\\\\Volume=\pi *(3cm)^{2} *2cm\\\\Volume=18\pi cm^{3} =56.54cm^{3}

3 0
2 years ago
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