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gavmur [86]
3 years ago
7

8. Solve the system using substitution. Show all work. (3 points)

Mathematics
1 answer:
Minchanka [31]3 years ago
3 0
Ok. first you have to pick x or y or whatever variable you have and the number multiplied with it has to be the same in each equation but one has to be positive and one negative.
lets pick x

y=-2x+6
3y=x-3/ *2

so the x are positive and negative we have to multiply the equation with 2

y=-2x+6
6y=2x-6

now you have to add the equations. you do that by adding each side of the equatins together like this:

y+6y=-2x+6+2x-6 the x will cancel out

7y=0
y=0

now just go back to one of the previous equations and put the y in it.

0=-2x+6
2x=6
x=3

here you go
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Furkat [3]

Answer:

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Step-by-step explanation:

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PLEASE HELP!!! Use sigma notation to represent the following series for the first 12 terms.
MariettaO [177]
If you notice, in the sum the terms are 2, -8, 32, -128....

we can always get the "common ratio" of a geometric sequence by dividing the "following term by the previous term", namely like in this case say -8/2, which is -4, so r = -4, and we know the first term is 2.

so, notice, the pattern will then be

 \bf \stackrel{2(-4)^0}{2}~~\stackrel{2(-4)^1}{-8}~~\stackrel{2(-4)^2}{32}~~\stackrel{2(-4)^3}{-128}\qquad \implies \qquad \sum\limits_{k=0}^{11}~2(-4)^k
4 0
3 years ago
A particle moves on the circle x2 y2=25 in the xy-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=
stiks02 [169]

The movement of the particle on the circle is its displacement.

The value of dy/dt at this time is -9/2.

<h3>What is the differentiation?</h3>

Differentiation is a process, in Maths, where we find the instantaneous rate of change in function based on one of its variables.

A particle moves on the circle x^2 + y^2=25 in the XY-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=6.

The equation of the circle is given as:

\rm x^2 + y^2=25

Differentiate with respect to time

\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0

Substitute all the values in the equation

\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0\\\\2(3) \times 6+2(4)\times \dfrac{dy}{dt}=0\\\\ 6 \times 6+8 \times \dfrac{dy}{dt}=0\\\\  36+8\times \dfrac{dy}{dt}=0\\\\ 8\times \dfrac{dy}{dt}=-36\\\\ \dfrac{dy}{dt}= \dfrac{-36}{8}\\\\ \dfrac{dy}{dt}= \dfrac{-9}{2}

Hence, the value of dy/dt at this time is -9/2.

Learn more about differentiation here;

brainly.com/question/19385433

#SPJ4

6 0
2 years ago
Select the correct answer.
kompoz [17]

Given:

The function is

f(x)=4x+9

Domain = {-4, -2, 0, 2}

To find:

The range of the given function for the given domain.

Solution:

We know that domain is the set of input values and range is the set  of output values.

We have, f(x)=4x+9 and domain = {-4, -2, 0, 2}.

Putting x=-4 in the given function, we get

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Putting x=-2 in the given function, we get

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f(-2)=1

Putting x=0 in the given function, we get

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The output values are -7, 1, 9, 17. So, the range of the function f(x) for the given domain is {-7, 1, 9, 17}.

Therefore, the correct option is D.

8 0
3 years ago
Belle walks n mile each morning and 16 miles each evening.
Rom4ik [11]

This makes no since.

6 0
3 years ago
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