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3 years ago

9

two groups go to a sporting event. The first buys 2 tickets and 1 child ticket for $39. The other buys 3 adult tickets and 1 chi

ld ticket for $56. How many dollars does it cost to purchase an adult ticket to the sporting event?

1 answer:

dexar [7]3 years ago

7 0

$17 for an adult ticket

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¿cuáles son los criterios de congruencia y semejanza de triángulo?

mars1129 [50]

Answer:

Two triangles are similar if they meet one of the following criteria. : Two pairs of corresponding angles are equal. : Three pairs of corresponding sides are proportional. : Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

Dos triángulos son similares si cumplen uno de los siguientes criterios. : Dos pares de ángulos correspondientes son iguales. : Tres pares de lados correspondientes son proporcionales. : Dos pares de lados correspondientes son proporcionales y los ángulos correspondientes entre ellos son iguales.

Step-by-step explanation:

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2 years ago

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Solve x+y=7 and 3x-2y=11 using elimination

BartSMP [9]

X=5 and y =2.
Here's how you do it.
Multiply the first equation by -3, and the second one by 1.
add the equations to eliminate x.
then solve for y by dividing both sides by -5, which gives us 2.
to solve for x subsitute 2 in for y.

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3 years ago

Write equations for the horizontal and vertical lines passing through the point , −8−5.

Allisa [31]

Step-by-step explanation:

sorry I don't know about this

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3 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

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2 years ago

2(x−3)=(x−1)+7

Oksanka [162]

Answer:

x = 12

(getting to the 20 character limit, please ignore this)

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2 years ago

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