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ololo11 [35]
2 years ago
14

What is the hydronium ion concetration of a ph=9. 2 solution

Chemistry
1 answer:
serg [7]2 years ago
3 0

The hydronium ion concentration of a pH = 9.2 of solution is 6.3 × 10⁻¹⁰M.

<h3>How do we calculate pH?</h3>

pH of the solution is define as the negative logarithm of the concentration of the hydronium ion as:

pH = -log[H⁺]

Or [H⁺] = 10^{-pH}

Given that pH value = 9.2

On putting values, we get

[H⁺] = 10^{-9.2} = 6.3 × 10⁻¹⁰M

Hence required concentration of hydronium ion is 6.3 × 10⁻¹⁰M.

To know more about pH, visit the below link:

brainly.com/question/172153

#SPJ2

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How many electrons could have the following set of quantum numbers?.
aleksley [76]

Answer:

2

Explanation:

As only 2 electrons can present in an orbital, so only 2 electrons in an atom can have this set of quantum numbers.

8 0
3 years ago
How many grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution?
Alexus [3.1K]

Answer: 724.71 grams

Explanation:

Volume of solution (v) = 5.1 liters

Concentration of solution (c) = 1.4M

Amount of CuF2 needed (n) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.4M x 5.1 Liters

n = 7.14 moles

Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.

The atomic masses of Copper = 63.5g;

and Fluorine = 19g

So, I CuF2 = 63.5g + (19g x 2)

= 63.5g + 38g

= 101.5g/mol

Then, apply the formula

Number of moles = mass in grams / molar mass

7.14 moles = m / 101.5 g/mol

m = 7.14 moles x 101.5 g/mol

m = 724.71g

Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution

7 0
4 years ago
A solid mass of 25g is added to a solution with the mass of 60g. The final mass of the solution is 75g. Explain why the mass of
Ann [662]

It is not equal because it dose not obey the conservation of mass. 60+25= 85 not 75.

4 0
4 years ago
1 pts
soldier1979 [14.2K]

Answer:

144 g

Explanation:

Use the mole ratio of 4 mol CO2 for every 9 mol O2 to convert from mol O2 to mol CO2. Then use the molar mass of CO2 to convert from mol of CO2 to grams of CO2.

7.34 mol O2 • (4 mol CO2 / 9 mol O2) • (44.01 g CO2 / 1 mol CO2) = 144 g CO2

5 0
3 years ago
Read 2 more answers
What would cause entropy to increase in a reaction?
gladu [14]

i think A but if I'm wrong sorry

then if increasing then becoming spread out so letter A

6 0
3 years ago
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