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d1i1m1o1n [39]
4 years ago
13

How many grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution?

Chemistry
1 answer:
Alexus [3.1K]4 years ago
7 0

Answer: 724.71 grams

Explanation:

Volume of solution (v) = 5.1 liters

Concentration of solution (c) = 1.4M

Amount of CuF2 needed (n) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.4M x 5.1 Liters

n = 7.14 moles

Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.

The atomic masses of Copper = 63.5g;

and Fluorine = 19g

So, I CuF2 = 63.5g + (19g x 2)

= 63.5g + 38g

= 101.5g/mol

Then, apply the formula

Number of moles = mass in grams / molar mass

7.14 moles = m / 101.5 g/mol

m = 7.14 moles x 101.5 g/mol

m = 724.71g

Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution

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PLEASE PLEASE HELP ME!! I WILL BRAINLIST YOU!! A 28.0 g sample of N2 is in a rigid 4.50 L container at 32 °C. Calculate the pres
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Answer:

P=4184.36 torr

Explanation:

For this problem we can use the idea gas law,

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the constant, and T is temperature, We will need to manipulate it and a couple values so that we can get our answer in torr. To do this, let's rearrange the equation to solve for P.

P=\frac{nRT}{V}

Next, let's convert T (32) to kelvin. To do this, add 273 to the value.

32+273=305

Next, let's convert 28g of N2 to moles of N2. To do this, divide 28 by the molar mass of N2 (28.02)

\frac{28.0}{28.01} \\=.99 moles of N2

Next, we need to find out what value of R we need to use. Because you want your answer in torr, we will need to use the value of

R=62.36\frac{torr}{mol*K}

Now that we have all of our values, let's plug them into the equation (I'll be excluding units for simplicity but they cancel out to leave units of torr in the answer)

P=\frac{(.99)(62.36)(305)}{4.50}\\P=4184.36

P=4184.36 torr

<em>Very briefly</em>, I don't know what your periodic table looks like, but mine has nitrogen's molar mass as 14.01. If you have a different mass of nitrogen, this pretty drastically impacts the value. For example, if your nitrogen's molar mass was rounded to 14.0 (making N2 28g) then it would be one mole instead of .99 moles, raising the answer to 4228.70 torr. If you have any different values just plug them in in their proper spots. A similar concept applies to the Kelvin conversion.

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