Since the rate of descent is a constant this is a linear equation and can be expressed as:
h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)
h=-2t+b, using the point (3,67) we can solve for b, or the initial height
67=-2(3)+b
67=-6+b
73=b so the initial height was 73 ft and the height equation is then:
h(t)=67-2t so when t=8 you have:
h(8)=67-2(8)
h(8)=67-16
h(8)=51 ft
Answer:
A) 24
Step-by-step explanation:
4!
4 x 3 x 2 x 1
24
Answer:
3 hours
Step-by-step explanation:
speed of Bharat = 12kilometers / hour
speed of Ingrid=14 kilometers / hour
For this problem we'll be using formula relating time, distance and speed.i.e
Distance = speed x time
Suppose Bharat is riding at a distance of 'b' kilometers, therefore time taken by him will be:
Time = distance/ speed
Time= b/12 hours.
Also, Ingrid can ride the distance at this time with speed of 14km/hr
The distance would be,
Distance = speed x time
Distance = 14 x (b/12) => 14b/12
Distance= 7b/6
Let '' be the distance that Bharat have covered after time 't'
therefore, = 12 x t
Let ' ' be the distance that Ingrid have covered after time 't'
therefore, = 14 x t
In order to find the time when they are 78 kilometers apart, we will add and , because they are travelling in opposite direction creating distance between them.
So,
+ = 78
( 14 x t) + (12 x t) =78
14t + 12t =78
26t= 78
t= 78/26
t= 3hours.
thus, it will take 3 hours until they are 78 kilometers apart
(-2+3)/(6+4)= 1/10
y+3=1/10(x + 4)
y + 3 = (1/10)x + 4/10
y + 30/10 = ( 1/10)x + 4/10
y = (1/10)x + 4/10 - 30/10
y = (1/10)x - 26/10
y = (1/10)x - 13/5
10(y = (1/10)x - 13/5)
10y = x - 26
-x + 10y = -26