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Ipatiy [6.2K]
3 years ago
5

ABC paint company needs to paint the outside of the building shown. They will also need to paint the roof. What is the surface a

rea that needs to be painted?
Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0

Answer:

3100 ft2

Step-by-step explanation:

Cloud [144]3 years ago
3 0
Given:

An unpainted roof. Assuming the dimensions of the roof are 10 meters by 5 meters by 0.2 meters. To solve for the total surface area of the roof to be painted:

SA = 2 (wl + lh + wh)
SA = 2 ( 10*5 + 10*0.2 + 5*0.2)
SA = 106 square meters

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I need help on these question ASAP!!!! This is Urgent
GarryVolchara [31]

Part 1: The equation of the line is y=2x+1

Part 2: The equation of the line in slope intercept form is y=-3x-1

Explanation:

Part 1: It is given that the point A is (1,3) and the line B is y=2 x-2

To determine the line passing through the point A and parallel to line B, let us first determine the slope and y-intercept.

From the equation of line B, the slope is m=2

Substituting the point (1,3) and m=2 in slope intercept form y=mx+b, we have,

3=2(1)+b

3=2+b

1=b

Thus, the y-intercept is b=1

Let us substitute the values m=2 and b=1 in the slope intercept form y=mx+b, we get,

y=2x+1

Thus, the equation of the line passing though point A and parallel to line B is y=2x+1

Part 2: The given two coordinates are (-1,2) and (1,-4)

To determine the equation of line in slope intercept form, first we shall find the slope and y-intercept.

From the graph, we can see that the line touches the y-axis at -1.

Hence, the y-intercept is b=-1

The formula for slope is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substituting the coordinates (-1,2) and (1,-4), we have,

m=\frac{-4-2}{1+1} =\frac{-6}{2} =-3

Thus, the slope is m=-3

Substituting the values b=-1 and m=-3 in the slope intercept formula y=mx+b, we get,

y=-3x-1

Thus, the equation of the line in slope intercept form is y=-3x-1

4 0
3 years ago
Total liabilities of $5000000. Net worth balance4000000. Calculate the debt to worth ratio?
blagie [28]

Answer:

5/4 or   1   1/5

Step-by-step explanation:

remove the zeros and you get 5/4 or   1  1/5

7 0
3 years ago
One solution to 3x+9+4x+x
Katyanochek1 [597]

Answer:

8x+9

Step-by-step explanation:

Add the like terms together.

3x+9+4x+x = 8x+9

5 0
3 years ago
Read 2 more answers
Christina is making a salad for a dinner party with 1.78 pounds of lettuce and 4.36 pounds of tomatoes.
gizmo_the_mogwai [7]

Answer:

A) 2.58 pounds

Step-by-step explanation:

To solve you would have to subtract the pounds of tomatoes from the pounds of lettuce. The equation would look like this,

4.36 - 1.78 = 2.58

Hope that helps and have a great day!

6 0
3 years ago
Helppp me plsssssssss<br><br>​
Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

  • \sf \:\:\:\:\:\:\:\:\:\:x_{k}=35
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k}=50
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42
  • \sf \:\:\:\:\:\:\:\:\:\:h=5

{\bf \:\: {By\:using\:the\: formula}} \\ \\

\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\

\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\

\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\

{\large{\frak{\pmb{\underline{Additional\: information }}}}}

MODE

  • Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

  • In a frequency distribution the class having maximum frequency is called the modal class.

{\bf{\underline{Formula\:for\: calculating\:mode:}}} \\

{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\

Where,

\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.

\small \blue{ \bigstar}\sf \: f_{k}=frequency\:of\:the\:modal\:class

\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class

\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class

\small \purple{ \bigstar}\sf \: h= width \:of\:the\:class\:interval

7 0
3 years ago
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