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Orlov [11]
3 years ago
7

1/2x+1/3y=5 and 1/4x+y=10 solve this system by substitution

Mathematics
1 answer:
qaws [65]3 years ago
5 0

Answer:

  (x, y) = (4, 9)

Step-by-step explanation:

You can use the second equation to write an expression for y.

  y = 10 - 1/4x . . . . subtract 1/4x from the given 2nd equation

Now, substitute that for y in the first equation:

  1/2x + 1/3(10 -1/4x) = 5

  1/2x + 10/3 -1/12x = 5 . . . . eliminate parentheses

You can work this a couple of ways from here. One is to multiply by 12 to eliminate fractions. Another is to work with the numbers as they are. We'll do that, because we don't get enough practice doing arithmetic with fractions.

  5/12x = 5/3 . . . . . subtract 10/3

  x = (5/3)/(5/12) = 12/3 = 4

From above, we can use our expression for y:

  y = 10 - 1/4·4 = 9

The solution is (x, y) = (4, 9).

 

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Evaluate for x and y<br> 4x-6y=-26<br> -2x+3y-13
kap26 [50]

Answer:

(x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb R

Step-by-step explanation:

4x-6y=-26

-2x+3y-13

4x-6y=-26

x=-13/2+3/2y

4(-13/2+3/2y) - 6y=-26

y in mathbb R

x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb

5 0
1 year ago
What form is this equation written in? y-7=2(x-6)
Alexxx [7]

Answer:

this is written in point slope form

Step-by-step explanation:

y-y1 = m(x-x1)

the slope is 2

and the point is (6,7)

7 0
3 years ago
Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
A line intersects the point (-3, -7) and
Anastaziya [24]

Answer:

y=-3x-16

Step-by-step explanation:

y-y1=m(x-x1)

y-(-7)=-3(x-(-3))

y+7=-3(x+3)

y=-3x-9-7

y=-3x-16

8 0
3 years ago
I really need help with this question <br> n+5≤16
ahrayia [7]

Answer:

the answer would be anything 11 and under (11,10,9,8,7,6,5,4,3,2,1,0)

Step-by-step explanation:

This is because if n+5 is less than or equal to 16 then 11+5=16 so that is equal to and less than would be using any number less than 11

hope this helps ;)

3 0
3 years ago
Read 2 more answers
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