Question

Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243, how many grams will remain after 12 days?

Answer 1

Answer:

The correct answer option is C. 4.18 g.

Step-by-step explanation:

We are given that Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243 and we are to find how many grams will remain after 12 days.

To find the number of remaining grams, we will use the following formula:

$A(t)=A_0(\frac{1}{2}) ^{\frac{t}{h} }$

where t is the time and h is the half life.

So substituting in the given values to get:

$A(t)=5.6(\frac{1}{2} )^{\frac{12}{28.5} }$

$A(t)=5.6*0.747$

$A(t)=4.18$

Therefore, 4.18 grams of curium-243 will remain after 12 days.

Answer 2

Answer:

C.4.18g

The amount will remain after 12 days is 4.18 g

Step-by-step explanation:

we can use formula

$P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }$

where

h is half life time

t is time in days

Po is initial quantity

P(t) is the quantity after t days

we are given

Curium-243 has a half-life of 28.5 days

$h=28.5$

In a sample of 5.6 grams of curium-243

so,

$P_0=5.6$

now, we can plug values

$P(t)=5.6(\frac{1}{2})^{\frac{t}{28.5} }$

now, we can plug t=12

$P(12)=5.6(\frac{1}{2})^{\frac{12}{28.5} }$

$P(12)=4.18253$

So,

The amount will remain after 12 days is 4.18 g