We will solve this by suing simultaneous equations,
⇒ 5s + 3j = 87
4s + 2j = 64
Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,
⇒ (5s + 3j = 87) × 4
(4s + 2j = 64) × 5
∴ ⇒ 20s + 12j = 348
20s + 10j = 320
Subtract both the equations. This is how your result (after subtraction) should look like,
⇒ 2j = 28
∴ ⇒ j = $14
Now replace the value of 'j' in one of the original equations,
⇒ 4s + 2(14) = 64
⇒ 4s + 28 = 64
⇒ 4s = 64 - 28
⇒ 4s = 36
∴ ⇒ s = $9
Therefore, one pair of jeans cost $14 and a shirt costs $9
Hope you understood! Feel free to ask me if you didn't understand a step.
Answer:
32º
Step-by-step explanation:
Fº-32 ×5/9
5/9Fº-160/9
5/9Fº =160/9
(5Fº)9=9(160)
45Fº=1440
divide both sides by 45
Fº=32
3/4 × 2 2/5
Turn 2 2/5 into an improper fraction.
2 2/5 = (5 × 2) + 2 = 12
So, 2 2/5 = 12/5
So, our new question is : 3/4 × 12/5
Multiply the numerators (top numbers) with one another.
Numerators : (3 × 12) = 36
Multiply the denominators (bottom numbers) with one another.
Denominators : (4 × 5) = 20
So, our answer is 36/20
However, we need this to be a mixed number.
So, how many times does 20 go into 36? Once!
So, Multiply 20 with 1, and then subtract that number from 36! :)
20 × 1 = 20
36 - 20 = 16
So, our answer is :
1 16/20
Then, you simplify it once more.
Divide the numerator and denominator by 4.
16 ÷ 4 = 4
20 ÷ 4 = 5
So, our final answer is 1 4/5
~Hope I helped!~
Answer:
dogs - 13
cats - 39
Step-by-step explanation:
Let the number of dogs Ma Bernier have be represented with d
She has 3 times as many cats as dogs, the number of cats she has :
cats = 3d
The sum of the cats and dogs is 52
d + 3d = 52
4d = 52
divide both sides of the equation by 4
d = 13
She has 13 dogs
Cats = 3d
= 3 x 13 = 39
