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Zepler [3.9K]
3 years ago
11

Which description most accurately summarizes the samples results? Help

Mathematics
2 answers:
Klio2033 [76]3 years ago
3 0

Answer:

I do it's option B your welcome!

Ede4ka [16]3 years ago
3 0

Answer:

<h2>The range is more consistent with pure cow manure, but the mixture of cow manure and mashed bananas creates more biogas overall.</h2>

Step-by-step explanation:

In this data, there are two true facts, <em>if cow manure and mashed bananas are mixed, then there would be more biogas, more energy. </em>The second fact is that <em>the range of both box plots is not the same.</em>

<h3>Pure cow manure's range: </h3>

Higher \ value - Lower \ value=26-10=16

<h3>The mixture's range:</h3>

Higher \ value - Lower \ value=50-22=28

<em>There are different ranges.</em>

Therefore, based on these two facts, the right answer is the upper right, because other options violate these facts given.

So, the range is more consistent with pure cow manure, but the mixture of cow manure and mashed banana creates more biogas overall.

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Kisachek [45]
A = pi * r^2.....r = radius and pi = 3.14

A = (3.14)(13^2)
A = 3.14(169)
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7 0
3 years ago
What segment is congruent to AC?<br> A. BD<br> B. BE<br> C. CE<br> D. none
Phoenix [80]
You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.

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Now, find another segment that also has a length of 6.

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So, the segment congruent to AC is B. BE . 
8 0
3 years ago
Solve for p: 6p + 6 = 13 + 5p
Ivan

Answer:

p equals 7

Step-by-step explanation:

6p + 6 = 13 + 5p

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7 0
3 years ago
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chubhunter [2.5K]

Answer:

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Step-by-step explanation:

\dfrac{2\sin^2{\alpha}-1}{\sin{\alpha}+\cos{\alpha}}=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{(\sin{\alpha}+\cos{\alpha})(\sin{\alpha}-\cos{\alpha})}\\\\=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{\sin^2{\alpha}-\cos^2{\alpha}}=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{\sin^2{\alpha}-(1-\sin^2{\alpha})}\\\\=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{2\sin^2{\alpha}-1}\\\\=\sin{\alpha}-\cos{\alpha}

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