A line passes through the two points (-4,6) and (2,-5). Calculate the following parts:
1 answer:
A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
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The set of equation that is known to have 5 and 0 as solutions is A and B.
<h3>How to solve for the system of equations.</h3>From the graph that we have here in this question, we are supposed to identify the equations that have this point.
We can do this by tracing the lines in order to locate 5 and 0 on the grid.
When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.
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Given:
Radius of the circle = 10 in
Central angle of the sector = 45 degrees
To find:
The area of the sector.
Solution:
Area of a sector is
Where, is the central angle in degrees.
Putting r=10 and , we get
Therefore, the area of the sector is 12.5π sq. inches.