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EleoNora [17]
1 year ago
13

A line passes through the two points (-4,6) and (2,-5). Calculate the following parts:

Mathematics
1 answer:
Viktor [21]1 year ago
8 0

A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.

<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>

Its slope would be:

m = \dfrac{y-q}{x-p}

The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.

The slope m of the line is given as

m = \dfrac{y-q}{x-p}\\\\ m = \dfrac{-5-6}{2+4}\\\\ m = \dfrac{-11}{6}

The equation of a line is  

( y -y_0) = m (x - x_0)\\\\( y -6) = \dfrac{-11}{6}  (x+4)\\\\6( y -6) = (-11)  (x+4)\\\\6y -36 = (-11x +44)\\\\11x +6y - 80 = 0

Hence, the equation is  11x +6y - 80 = 0

Learn more about slopes here:

brainly.com/question/2503591

#SPJ4

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Step-by-step explanation: i hope that helps buddy :)

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