Answer:
A) 17 m B) 20.8 m
Step-by-step explanation:
I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11
26-11 = 15
I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)
AB is the hypotenuse
We can use the pythagorean theorem to find length AB (a^2 + b^2 = c^2)
a and b is the legs which is 8 and 15
8^2 + 15^2 = AB^2
64 + 225 = AB^2
289 = AB^2
√289 = AB (to undo a square, you use square roots)
√289 = 17
AB = 17 m
Now we need to find the hypotenuse of AC
the same thing, we did for problem A, use the pythagorean theorem
17^2 + 12^2 = AC^2
289 + 144 = AC^2
433 = AC^2
√433 = AC
√433 is <em>about </em>20.808...
round to the tenth as stated in the directions
AC = 20.8 m
Answer:
The land area of Florida is 
Step-by-step explanation:
Let
x -----> the land area of Alaska in square miles
y -----> the land area of Florida in square miles
we know that
The linear equation that represent this problem is equal to
----> equation A
----> equation B
substitute equation B in equation A and solve for y
Remember that
Florida's land area is one-tenth the size of Alaska is the same as to say that Alaska's land area is ten times the size of Florida
I wouldn’t trust the links to a “photo” like the people in the comments said. If you give me the equation of the line the question is taking about I could solve it for you.
Step-by-step explanation:
Inverse of
y
=
x
+
3
x
−
2
is
y
=
2
x
+
3
x
−
1
Explanation:
As
y
=
x
+
3
x
−
2
x
y
−
2
y
=
x
+
3
or
x
y
−
x
=
2
y
+
3
or
x
(
y
−
1
)
=
2
y
+
3
or
x
=
2
y
+
3
y
−
1
Hence inverse of
y
=
x
+
3
x
−
2
is
y
=
2
x
+
3
x
−
1
Observe that each of the function is a reflection of the other in the line
x
=
y
.
graph{(y-(x+3)/(x-2))(y-(2x+3)/(x-1))(x-y)=0 [-10, 10, -5, 5]}
Step-by-step explanation:
Any positive number can. be a side length. It cannot pass 7 because a square with 49 sqr lnches as a area has side lengths with the measures of 7.
