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2 years ago

Quadrilateral ABCD has vertices at A(-4,5) B(-1,9) C(7,3) and D(4,-1). What is the most precise name for a quadrilateral ABCD?

Mathematics

1 answer:

Temka [501]2 years ago

5 0

Answer:

Rectangle

Step-by-step explanation:

The answer you put was a rhombus , which is wrong . if you put the coordinates in you would see that its a rectangle slightly tilted instead of rhombus , a rectangle has more of a wider side than a rhombus does . please change your answer!

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Figure 1

hodyreva [135]

Tip: Go to the internet and put the topic you are focused more on that you posted in Brainly

Step-by-step explanation:

Try it to give you some help

4 0

2 years ago

A sunflower is 15 inches tall and grows 2 inches a week. How many weeks will it take for the

Zarrin [17]

Answer:

4 weeks

Step-by-step explanation:

15 + 2x = 23

2x = 8

x = 4

8 0

2 years ago

Determine the next step for solving the quadratic equation by completing the square

GaryK [48]

Answer:

The two solutions are: $x=\frac{1}{2}+/-\frac{\sqrt{7} }{2}$

The next and every step are below.

Explanation:

1. $-3=-2x^2+2x$ : Given (addition property / add - 3 to both sides)

2. $-3 = - 2(x^2-x)$ : Given (commom factor - 2)

3. $-3-1/2=-2(x^2-x+1/4)$

To obtain the perfect square it was added the square of half of the coefficient of x: (1/2)² = 1/4, inside the parenthesis.

Since, the terms inside the parentthesis are multiplied by - 2, you have to add - 2 (1/4) = - 1/2 to the left side of the equation.

4. Now, you have that the trinomial x² - x + 1/4 is a square perfect trinomial which is factored as (x - 1/2)² and get the expression:

$-7/2=-2(x-1/2)^2$

5. Divide both sides by - 2 to get the next expression:

$-7/4=(x-1/2)^2$

6. The last step is to extract squere root from both sides of the equality:

$(x-1/2)=+/-\sqrt{\frac{7}{4}}\\ \\ x-1/2=+/-\frac{\sqrt{7} }{2}\\ \\ x=\frac{1}{2}+/-\frac{\sqrt{7} }{2}$

8 0

3 years ago

Pls help with 29..tank you

trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the 2 roots be A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 = ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 = 3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

3 0

3 years ago

Read 2 more answers

If the sum of the roots of the equation 3x² + kx + 1 = 0 is 7. then what the value of k

koban [17]

Answer:

The value of k is -21

Step-by-step explanation:

ax² + bx + c = 0

Sum of the roots = -b/a

3x² + kx + 1 = 0

= sum of the roots = -k/3

-k/3 = 7

Now, Multiply both side by (-3) we get,

(-3)-k/3 = 7(-3)

k = -21

Thus, The value of k is -21

<u>-TheUnknownScientist</u><u> 72</u>

7 0

2 years ago