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ivann1987 [24]
2 years ago
7

Quadrilateral ABCD has vertices at A(-4,5) B(-1,9) C(7,3) and D(4,-1). What is the most precise name for a quadrilateral ABCD?

Mathematics
1 answer:
Temka [501]2 years ago
5 0

Answer:

Rectangle

Step-by-step explanation:

The answer you put was a rhombus , which is wrong . if you put the coordinates in you would see that its a rectangle slightly tilted instead of  rhombus , a rectangle has more of a wider side than a rhombus does . please change your answer!

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34kurt
I do not have an answer for that, but you should try looking for that on google or yahoo answers.
8 0
3 years ago
Please help !!
Maurinko [17]
Answer: The number of ceral boxes per day.

Because the slope will be [rise of the grah of the model function] / [run of the graph of the model function].

rise = [increase in the number of cereal boxes sold]

run = [days elapsed ]

rise / run = number of cereal boxes sold per day


8 0
4 years ago
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Using the unpaid balance​ method, find the current​ month's finance charge on a credit card account having the following transac
Reptile [31]

Answer:

33333333330000000000

5 0
3 years ago
Please help me find
erica [24]

Answer:

150 feet

Step-by-step explanation:

the ratio of her shadow to her height

2/5=60/150

60/150=2/5

i hope it is right

3 0
3 years ago
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Use the quadratic formula to find the solutions to the quadratic equation below 2x^2-5x+5=0
Serggg [28]

Answer:

x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

Step-by-step explanation:

Solve for x:

2 x^2 - 5 x + 5 = 0

Hint: | Using the quadratic formula, solve for x.

x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:

x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4

Hint: | Express sqrt(-15) in terms of i.

sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):

Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

5 0
4 years ago
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