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kakasveta [241]
2 years ago
7

Mark said, "in the data set,4, 5, 5, 8, the mean and mode the same. " Is he correct? Explain why or why not in your explanation

make sure to state the value of the the means and the mode
Mathematics
1 answer:
Vinvika [58]2 years ago
5 0

Answer:

No

Step-by-step explanation:

the mean is 16 (add 4+5+5+8, then divide answer by 4) and the mode is 5 (occurs most in data)

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EXPLANATION

The volume of a sphere is given by the following relationship:

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Replacing terms:

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Each investment matures in 3 years. The interest compounds annually.
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bearing in mind that 4¾ is simply 4.75.

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$600\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases} \\\\\\ A=600\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies A=600(1.05)^3\implies A=694.575 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$750\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases} \\\\\\ A=750\left(1+\frac{0.0475}{1}\right)^{1\cdot 3}\implies A=750(1.0475)^3\implies A\approx 862.032

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695.575 - 600 = 95.575.

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Step-by-step explanation:

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