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marta [7]
3 years ago
11

What is the solution to 4x-8=12 please explain.

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0

Answer:

One solution, x=5.

Step-by-step explanation:

4x-8=12

To find the solution we have to find the value of x.

to find the value of x, we have to add 8 to BOTH sides.

4x-8=12   (Why add 8? because we have to do the opposite of the sign!)

   +8  +8

4x=20

Now to find X we have to ISOLATE IT.

So we take out 4, How? We do the opposite to both sides.

4/4 Cancels out

20/4 = 5

So now we know X=5

Insert in the main problem to check.

4(5)-8=12

20-8=12

12=12

dedylja [7]3 years ago
3 0

Answer:

x=5

Step-by-step explanation:

4x−8=12

Step 1: Add 8 to both sides.

4x−8+8=12+8

4x=20

Step 2: Divide both sides by 4.

4x

4

=

20

4

x=5

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Jane is 5 times older than her sister. In 3 years, Jane’s sister will be 1/4 her age. Find the ages now
Korolek [52]

The present age of Jane is 45 years old and present age of her sister is 9 years old

<em><u>Solution:</u></em>

Let the present age of Jane be "x"

Let the present age of her sister be "y"

<em><u>Jane is 5 times older than her sister</u></em>

present age of Jane = 5(present age of her sister)

x = 5y ---------- eqn 1

<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>

Age of sister after 3 years = 3 + y

Age of jane after 3 years = 3 + x

Age of sister after 3 years = 1/4(age of jane after 3 years)

3 + y = \frac{1}{4}(3 + x)

Substitute eqn 1 in above equation

3 + y = \frac{1}{4}(3 + 5y)\\\\12 + 4y = 3 + 5y\\\\5y - 4y = 12 - 3\\\\y = 9

Substitute y = 9 in eqn 1

x = 5(9)

x = 45

Thus present age of Jane is 45 years old and present age of her sister is 9 years old

3 0
3 years ago
Maria y juan deben realizar el mapamundi en medio pliego de cartulina para la tarea de sociales pero cada uno tiene un cuarto de
kondor19780726 [428]

Answer:

Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:

  • <u>Verdadero</u>.

Step-by-step explanation:

Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:

  • Total de cartulina de María y Juan = \frac{1}{4}+\frac{1}{4}
  • Total de cartulina de María y Juan = \frac{4+4}{16}
  • Total de cartulina de María y Juan = \frac{8}{16}

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:

  • Total de cartulina de María y Juan = \frac{4}{8}
  • Total de cartulina de María y Juan = \frac{2}{4}
  • <u><em>Total de cartulina de María y Juan = </em></u>\frac{1}{2}<u><em /></u>

Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.

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B.

I took the test :)
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