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rjkz [21]
2 years ago
14

What is the quotient of 5 7 ÷ 5 14 ?

Mathematics
1 answer:
KatRina [158]2 years ago
3 0

Answer:

<h2><u>=</u> <u>   57 / 514  </u>    <u>(Decimal: 0.110895)</u></h2>

Step-by-step explanation:

57 / 514

<u>=   57 / 514 </u>

<u>(Decimal: 0.110895)</u>

<u></u>

<u></u>

<u></u>

<u></u>

<u></u>

<u></u>

<u></u>

<u></u>

<u></u>

<h2><u>And if that is not what you are looking for here: </u></h2><h2><u></u></h2>

Rewrite the equation as  

x /14 =  5/ 7 .  x/ 14 =  5/ 7

Multiply both sides of the equation by  

14.14  ⋅  x /14 =  14 ⋅ 5 /7

Simplify both sides of the equation.

Tap for fewer steps...

Cancel the common factor of  14 .  

Cancel the common factor.

14 ⋅  x /14 =  14 ⋅ 5 /7

Rewrite the expression.

x = 14 ⋅ 5 /7

Simplify  14 ⋅  5/ 7 .

Cancel the common factor of  7 .

Factor  7  out of  14 .

x = 7 ( 2 ) ⋅ 5/ 7

Cancel the common factor.

x = 7 ⋅  2 ⋅  5/ 7

Rewrite the expression.

x  = 2 ⋅ 5

Multiply  2  by  5 .

<u>x = 10</u>

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There are 10 men and 14 women in Kathleen’s math class. What is the ratio of women to the total number of students in the class?
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Answer:

14 to 25

Step-by-step explanation:

there are 14 women and 24 people altogether

5 0
3 years ago
A 6 sided die was rolled 9 times. What is the mode of these rolls?
yuradex [85]
That 1,2,3,4,5,6 is one the die and it has a chance to at least get all the numbers at least once but u dont have enough data so i can help u more.
6 0
2 years ago
Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
2 years ago
If you select a card at random, what is the probability of getting:A number smaller than 5 (counting the ace as a 1)?
garri49 [273]

4 Aces, 4 2's, 4 3's 4 4's

= 16 cards total out of 52 cards

 so probability would be 16/52 which reduces to 4/13

4 0
3 years ago
EXPLAIN YOUR ANSWER
Bad White [126]
Solve the equation by substitution method.
To get b-2-3b=4. Then you substitute b into simplest to get, b=-3. Repeat the same process with a to get, a=-5. So your answer would be (-5, -3)
7 0
3 years ago
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