Answer:
SMTP
Explanation:
This is the SMTP or the Simple Mail Transfer Protocol. It is the push protocol and is used to send the mail message. Whereas POP3 and IMAP are meant for retrieving the message. These are the three main types of protocols associated with mail services. And the correct answer here is certainly the SMTP.
Answer:
Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say goodbye
Never gonna tell a lie and hurt you
Never gonna give, never gonna give
(Give you up)
We've known each other for so long
Your heart's been aching but you're too shy to say it
Inside we both know what's been going on
We know the game and we're gonna play it
I just wanna tell you how I'm feeling
Gotta make you understand
Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say goodbye
Never gonna tell a lie and hurt you
Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say goodbye
Never gonna tell a lie and hurt you
Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say goodbye
Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable
int num;
int tot_sum=0;
cout<<"enter a number: ";
// read the value of n
cin>>num;
// check the multiple of 2 or 5 from 1 to n
for(int x=1;x<=num;x++)
{
// if multiple of 2 or 5 then add them
if(x%2==0 ||x%5==0)
{
tot_sum=tot_sum+x;
}
}
// print the sum
cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;
return 0;
}
Explanation:
Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.
Output:
enter a number:11
sum of multiple of 2 or 5 is:35
Answer:
zero
Explanation:
Because of the define the product variable is zero.
when the function call with pass by value 4.
The program control moves to that function, after that product
store the value zero. Then, product is multiply with n which become zero
because 0 * n is zero and store in the product again.
after that, n'' is wrong it must be 'n--' for performing the factorial function.
after that, the value of n is 3, again loop execute because condition n > 0
is true.
again zero multiply with n and become zero.
this process repeated until condition false and finally the output is zero.
Correction:
To make the code working:
change product = 1 instead of zero.
and change n-- in place of n''.
No one could possibly know, unfortunately.
