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Answer:
The sum of all positive even values in arr
Explanation:
We have an array named arr holding int values
Inside the method mystery:
Two variables s1 and s2 are initialized as 0
A for loop is created iterating through the arr array. Inside the loop:
num is set to the ith position of the arr (num will hold the each value in arr)
Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).
When the loop is done, the value of s1 and s2 is printed.
As you can see, s1 holds the sum of positive even values in the arr
It is
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Answer: True
Explanation: For loop is used in the C++ programming is defined as the statement that defines about the flow control .This loop works under some condition that is considered.
For loop is evaluated to execute for one time if the statement condition is true but there are also chances of no execution at all because of the incorrect condition. So, for loop might not run even once in that condition.Thus , the statement given is true.
