Answer:
The answer is: second line indent
Explanation:
Also known as a second line indent, sets off the first line of a paragraph by positioning it at the margin, and then indenting each subsequent line of the paragraph.
Answer:
The correct answer is C. One reason why a business may want to move entirely online is to focus on a global market.
Explanation:
The fact that a business wishes to move entirely towards the online sales modality implies that there is a desire to expand the possibilities of selling its products beyond the physical place where it has its store.
It is a reality that starting an online business implies that the offered product can be purchased anywhere in the world, thanks to advances in technology and transportation that allow the product to be purchased and delivered in a matter of days, thanks to the advances produced by globalization.
Therefore, the fact that the store goes from physically to online selling makes its potential customers go from being the ones who know the store and live close to it to everyone in the world with access to internet.
Answer:
The correct answer is letter "C": encoding, storage, retrieval.
Explanation:
In psychology, the stages of memory are <em>encoding, storage, </em>and <em>retrieval</em>. Encoding refers to changing the information as it is received so it can be stored in the memory and imply inputs in three kinds: <em>visual (pictures), acoustic (sounds), </em>and<em> semantic (meaning)</em>. Storage is the stage in which the input is retained in the memory, where it is stored, and for how long. Finally, retrieval implies organizing information stored in the memory to recall it.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
