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2 years ago

Help ASAP PLEASE

1 answer:

4 0

Before school began, Mrs. Weeks bought a total of 86 balls. Total number of each type of ball 8. There are 18 Basketballs, 36 Baseballs, 15 Softballs

<h3>What is the unitary method?</h3>

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Before school began, Mrs. Weeks bought a total of 86 balls.

Total number of each type of ball 8.

footballs - There are 8 footballs.

Basketballs - Two more than twice the number of footballs are Basketballs .

So, Basketballs = 2 + 2(8)

= 18

Baseballs - Four less than 5 times the number of footballs are

Baseballs .

So, Baseballs = 5(8)- 4

= 36

Softballs - Six more than half of the baseballs are softballs.

So, Softballs = 6 + 1/2 baseballs are softballs

= 6 + 1/2 (18)

= 15

Learn more about the unitary method;

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Please help!

Dmitrij [34]

Answer:

$5.10

Step-by-step explanation:

15% of 34

15/100 × 34 = $5.10

3 0

3 years ago

The product of negative 5 and negative 4 increased by 3 equals

Goryan [66]

Answer : 23

-5 * -4 = 20 ( when you multiply 2 negatives the answer is always positive )

20 + 3 = 23

8 0

3 years ago

The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in in

Grace [21]

Answer:

A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Step-by-step explanation:

We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;

68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2, 76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.

Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;

P.Q. = $\frac{(n-1) \times s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation = $\sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} }$ = 5.063

$\sigma$ = population standard deviation

n = sample of observations = 22

Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.

<u>So, 90% confidence interval for the population standard deviation, </u> $\sigma$ <u> is ;</u>

P(11.59 < $\chi^{2}__2_1$ < 32.67) = 0.90 {As the critical value of chi at 21 degrees

of freedom are 11.59 & 32.67}

P(11.59 < $\frac{(n-1) \times s^{2} }{\sigma^{2} }$ < 32.67) = 0.90

P( $\frac{ 11.59}{(n-1) \times s^{2}}$ < $\frac{1}{\sigma^{2} }$ < $\frac{ 32.67}{(n-1) \times s^{2}}$ ) = 0.90

P( $\frac{(n-1) \times s^{2} }{32.67 }$ < $\sigma^{2}$ < $\frac{(n-1) \times s^{2} }{11.59 }$ ) = 0.90

<u>90% confidence interval for</u> $\sigma^{2}$ = [ $\frac{(n-1) \times s^{2} }{32.67 }$ , $\frac{(n-1) \times s^{2} }{11.59 }$ ]

= [ $\frac{21 \times 5.063^{2} }{32.67 }$ , $\frac{21 \times 5.063^{2} }{11.59 }$ ]

= [16.48 , 46.45]

<u>90% confidence interval for</u> $\sigma$ = [ $\sqrt{16.48}$ , $\sqrt{46.45}$ ]

= [4.06 , 6.82]

Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

5 0

3 years ago

I think its B

Galina-37 [17]

B is correct, good job

6 0

4 years ago

Read 2 more answers

A store is having a sale on trail mix and jelly beans. For 2 pounds of trail mix and 3 pounds of jelly beans, the total cost is

Rina8888 [55]

Answer:

trail mix: $1.25
jelly beans: $3.50 per pound

Step-by-step explanation:

The difference between double the first purchase and the second purchase is $7 and 2 pounds of jelly beans. Hence a pound of jelly beans is $3.50.

(4t +8j) -2(2t +3j) = (33) -2(13) . . . . . let t and j represent pounds of trail mix and jelly beans, respectively

2j = 7 . . . . . . . . . . simplify

j = 7/2 = 3.50

Using that value in the first purchase, we get ...

2t +3(3.50) = 13

2t = 13 -10.50

t = 2.50/2 = 1.25

A pound of trail mix is $1.25.

3 0

3 years ago