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Naddik [55]
3 years ago
10

Yenni is playing a card game where she is trying to collect on of each suit.There are 3 hearts 2 diamonds 1 spade and 4 clubs le

ft in the deck.What is the probability that she will pick a heart and a club without replacing the cards?
Mathematics
1 answer:
Gemiola [76]3 years ago
8 0

Answer:

27/40

Step-by-step explanation:

Probability of picking heart: 3 hearts/ 10 total

Probability of picking club: 4 clubs/ 9 left over cards

3/10 divided by 4/9= 27/40

Hope this helped

Please mark Brainliest

So i can rank up

;p

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bezimeni [28]
53.4 each dollar is 0.89 so x 60.
7 0
3 years ago
Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the
dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

I = \int \int_E \int zdV where E is bounded by the cylinder y^2 + z^2 = 81 and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and y^2 + z^2 = 81

∴ z^2 = 81 - y^2

z = \sqrt{81 - y^2}

Thus, z lies between 0 to \sqrt{81 - y^2}

GIven curve x = 0 and y = 9x

x =\dfrac{y}{9}

As such,x lies between 0 to \dfrac{y}{9}

Given curve x = 0 , x =\dfrac{y}{9} and z = 0, y^2 + z^2 = 81

y = 0 and

y^2 = 81 \\ \\ y = \sqrt{81}  \\ \\  y = 9

∴ y lies between 0 and 9

Then I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix}    ^ {\sqrt {{81-y^2}}}_{0} \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{(\sqrt{81 -y^2})^2 }{2}-0  \end {bmatrix}     \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{{81 -y^2} }{2} \end {bmatrix}     \ dxdy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0}    \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix}     \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81 \  y -y^3} }{18} \end {bmatrix}     \ dy

I = \dfrac{1}{18} \int^9_{y=0}  \begin {bmatrix}  {81 \  y -y^3}  \end {bmatrix}     \ dy

I = \dfrac{1}{18}  \begin {bmatrix}  {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}}  \end {bmatrix}^9_0

I = \dfrac{1}{18}  \begin {bmatrix}  {40.5 \ (9^2) - \dfrac{9^4}{4}}  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  3280.5 - 1640.25  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  1640.25  \end {bmatrix}

I = 91.125

4 0
3 years ago
A wooden box has the shape of a rectangular prism. The inside of the box is also a rectangular prism. What is the volume of the
ElenaW [278]
1560 cm^2 as you subtract the small prism from the large
5 0
2 years ago
Lisa is getting paid 96$ per hour, her salary per hour increases by 12%, how much is she getting paid now after in increases by
Bas_tet [7]

Answer:

96$/12×100

=8 × 100

=800$

5 0
2 years ago
Read 2 more answers
Q1: Payments of $ 670 are being made at the end of each month for 5 years at an interest of 8% compounded monthly. Calculate the
pishuonlain [190]

Answer:

1. $361800

Step-by-step explanation:

Given,

principle balance=$670

interest rate=8%

A=P(1+\frac{r}{n})(nt)

A= Final amount

P= initial Principal balance

r= interest rate

n= number of times interest applied per time period

t= number of times period elapsed

compound interest formula,A=670(1+\frac{8}{1})(60) )\\A=361800

Therefore the Present value is $361800

3 0
3 years ago
Read 2 more answers
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