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svetlana [45]
3 years ago
14

What is the image point of (1, -2) after a translation right 4 units and down 4 units?

Mathematics
1 answer:
zaharov [31]3 years ago
3 0
It would be 4 over -4
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X Cube - 5x Square - 2 x + 24​
Otrada [13]

Answer:

(x+2)(x-4)(x-3)

(x²-4x+2x-2)(x-3)

(x²-2x-2)(x-3)

=x³-5x²-2x+24

So the answer true

8 0
3 years ago
The ratio of volume of a cone and a hemisphere of same base radius and height is?
aliya0001 [1]

Answer:

1/2

Step-by-step explanation:

Since it is given that the cone and the hemisphere have the same height, and since the height of a hemisphere would be equal to its radius, the cones height must also be equal to its base radius.

With this information we can use the respective volume formulas.

Hemisphere:  \frac{2}{3}πr^3

Cone:  \frac{1}{3}πhr^2

Since h (height) = r we can say the cone volume equals:

\frac{1}{3}πr^3

Now to find the ratio we divide the cone volume equation by the hemisphere volume equation

pi and r^3 cancels out from the division and we are left with

ratio = (1/3)/(2/3)

ratio = 1/2

7 0
3 years ago
5. Emmanuel makes 82,000 as a software designer. Use the follow tax chart to find what he will pay in taxes this year.
Mekhanik [1.2K]
I think the answer is d
5 0
3 years ago
Δx→0 <br> −5(x + Δx) + 5x<br> Δx
marysya [2.9K]
I guess the original function was

y = 5x (1)

y+Δy =5(x+Δx) (2)

(2) - (1) =

Δy = 5Δx

Δx →0, Δy/Δx →5


7 0
3 years ago
Given a focus of (4, 5) and directrix of y= -3 , find the equation of the parabola.
andrey2020 [161]
Check the picture below.

notice, the focus point is at 4,5 whilst the directrix line is at y = -3, below the focus point, meaning the parabola is vertical and opening upwards.

keeping in mind that the vertex is "p" distance from either of these fellows, then the vertex is half-way between both of them, notice in the picture, the distance from y = 5 to y = -3 is 8 units, half that is 4 units, thus the vertex 4 units from the focus or 4 units from the directrix, that puts it at (4,1), whilst "p" is 4, since the parabola is opening upwards, is a positive 4 then.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;(y-{{ k}})^2=4{{ p}}(x-{{ h}})&#10;\\\\&#10;\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=4\\&#10;k=1\\&#10;p=4&#10;\end{cases}\implies (x-4)^2=4(4)(y-1)\implies (x-4)^2=16(y-1)&#10;\\\\\\&#10;\cfrac{1}{16}(x-4)^2=y-1\implies \cfrac{1}{16}(x-4)^2+1=y

8 0
3 years ago
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