Question

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Answer 1

Answer:

A. A=10

Step-by-step explanation:

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Answer 2

The equation of the ellipse is required \frac{(x)^2}{16} +\frac{(y+4)^2}{25}=1

The required equation is

$\frac{x^2}{16} +\frac{(y+4)^2}{25}=1$

It can be seen that the major axis is parallel to the y axis.

The major axis points are

$(h,k+a)=(0,1)\\(h,k-a)=(0,-9)\\k+a=1\\k-a=-9$

Subtracting the equations

$2a=10\\\implies a=5$

The foci are

$(h,k+c)=(0,-1)\\(h,k-c)=(0,-7)$

$k+c=-1\\k-c=-7$

Subtracting the equations

2c=6

c=3

k+c=-1 implies that k=-1-c

k=-1-3

k=-4

What is the equation of the ellipse?

$\frac{(x-h)^2}{b^2} +\frac{(x-h)^2}{a^2}=1$

So we get,

$\frac{(x-0)^2}{4^2} +\frac{(y+4)^2}{5^2}=1$

$\frac{(x)^2}{16} +\frac{(y+4)^2}{25}=1$

Therefore the equation is, $\frac{(x)^2}{16} +\frac{(y+4)^2}{25}=1$.

To learn more about the ellipse visit:

brainly.com/question/450229