The answer is D. 168 units^3
Answer:
Step-by-step explanation:
![12.\ \frac{2}{3}x+2=16 < == subtract\ 2\ from\ both\ sides \\\\.\ \ \ \ \ \ \ \ -2 \ -2\\\frac{2}{3}x=14 < == multiply\ both\ sides\ by\ 3 \\\\3( \frac{2}{3}x=14)\\\\2x=42 < == divide\ both\ sides\ by\ 2\\/2 \ \ \ /2\\\\x=21 < == final\ answer](https://tex.z-dn.net/?f=12.%5C%20%5Cfrac%7B2%7D%7B3%7Dx%2B2%3D16%20%3C%20%3D%3D%20subtract%5C%202%5C%20from%5C%20both%5C%20sides%20%5C%5C%5C%5C.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20-2%20%5C%20-2%5C%5C%5Cfrac%7B2%7D%7B3%7Dx%3D14%20%3C%20%3D%3D%20multiply%5C%20both%5C%20sides%5C%20by%5C%203%20%5C%5C%5C%5C3%28%20%5Cfrac%7B2%7D%7B3%7Dx%3D14%29%5C%5C%5C%5C2x%3D42%20%3C%20%3D%3D%20divide%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%2F2%20%5C%20%5C%20%5C%20%2F2%5C%5C%5C%5Cx%3D21%20%3C%20%3D%3D%20final%5C%20answer)
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![\frac{2}{3}x+2=16\\\\\frac{2}{3}(21)+2=16\\\\\frac{42}{3}+2=16\\\\14+2=16\\\\16=16](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7Dx%2B2%3D16%5C%5C%5C%5C%5Cfrac%7B2%7D%7B3%7D%2821%29%2B2%3D16%5C%5C%5C%5C%5Cfrac%7B42%7D%7B3%7D%2B2%3D16%5C%5C%5C%5C14%2B2%3D16%5C%5C%5C%5C16%3D16)
This statement is correct
![13.\ \frac{x}{2} +\frac{x}{3} =\frac{5}{6} < == find\ the\ common\ denominator\ (6) \\\\\frac{3x}{6} +\frac{2x}{6} =\frac{5}{6} < == combine\ like\ terms \\\\\frac{5x}{6} =\frac{5}{6} < == divide\ both\ sides\ by\ \frac{5}{6} \\\\x=1 < == final\ answer](https://tex.z-dn.net/?f=13.%5C%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%5Cfrac%7Bx%7D%7B3%7D%20%3D%5Cfrac%7B5%7D%7B6%7D%20%3C%20%3D%3D%20find%5C%20the%5C%20common%5C%20denominator%5C%20%286%29%20%5C%5C%5C%5C%5Cfrac%7B3x%7D%7B6%7D%20%2B%5Cfrac%7B2x%7D%7B6%7D%20%3D%5Cfrac%7B5%7D%7B6%7D%20%3C%20%3D%3D%20combine%5C%20like%5C%20terms%20%5C%5C%5C%5C%5Cfrac%7B5x%7D%7B6%7D%20%3D%5Cfrac%7B5%7D%7B6%7D%20%3C%20%3D%3D%20divide%5C%20both%5C%20sides%5C%20by%5C%20%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%5C%5Cx%3D1%20%3C%20%3D%3D%20final%5C%20answer)
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![\frac{x}{2} +\frac{x}{3} =\frac{5}{6}\\\\\frac{1}{2} +\frac{1}{3} =\frac{5}{6}\\\\\frac{3}{6} +\frac{2}{6} =\frac{5}{6}\\\\\frac{5}{6}=\frac{5}{6}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%20%2B%5Cfrac%7Bx%7D%7B3%7D%20%3D%5Cfrac%7B5%7D%7B6%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B3%7D%20%3D%5Cfrac%7B5%7D%7B6%7D%5C%5C%5C%5C%5Cfrac%7B3%7D%7B6%7D%20%2B%5Cfrac%7B2%7D%7B6%7D%20%3D%5Cfrac%7B5%7D%7B6%7D%5C%5C%5C%5C%5Cfrac%7B5%7D%7B6%7D%3D%5Cfrac%7B5%7D%7B6%7D)
This statement is correct
![14.\ \frac{x-1}{6} -\frac{x+1}{8}=\frac{1}{12} < ==find\ the\ common\ denominator\ (24) \\\\\frac{24x-1}{6} -\frac{24x+1}{8}=\frac{24}{12}\\\\4(x-1) -3(x+1)=2 < ==distribute\\\\4(x)+4(-1) -3(x)+-3(1)=2\\\\4x-4-3x-3=2 < ==combine\ like\ terms\\\\x-7=2 < ==add\ 7\ to\ both\ sides\\\\.\ +7\ +7\\\\x =9 < == final\ answer](https://tex.z-dn.net/?f=14.%5C%20%5Cfrac%7Bx-1%7D%7B6%7D%20-%5Cfrac%7Bx%2B1%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B12%7D%20%3C%20%3D%3Dfind%5C%20the%5C%20common%5C%20denominator%5C%20%2824%29%20%5C%5C%5C%5C%5Cfrac%7B24x-1%7D%7B6%7D%20-%5Cfrac%7B24x%2B1%7D%7B8%7D%3D%5Cfrac%7B24%7D%7B12%7D%5C%5C%5C%5C4%28x-1%29%20-3%28x%2B1%29%3D2%20%3C%20%3D%3Ddistribute%5C%5C%5C%5C4%28x%29%2B4%28-1%29%20-3%28x%29%2B-3%281%29%3D2%5C%5C%5C%5C4x-4-3x-3%3D2%20%3C%20%3D%3Dcombine%5C%20like%5C%20terms%5C%5C%5C%5Cx-7%3D2%20%3C%20%3D%3Dadd%5C%207%5C%20to%5C%20both%5C%20sides%5C%5C%5C%5C.%5C%20%2B7%5C%20%2B7%5C%5C%5C%5Cx%20%3D9%20%3C%20%3D%3D%20final%5C%20answer)
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![\frac{x-1}{6} -\frac{x+1}{8}=\frac{1}{12}\\\\\frac{9-1}{6} -\frac{9+1}{8}=\frac{1}{12}\\\\\frac{8}{6} -\frac{10}{8}=\frac{1}{12}\\\\\frac{32}{24}- \frac{30}{24}=\frac{1}{12}\\\\\frac{2}{24}=\frac{1}{12}\\\\\frac{1}{12}=\frac{1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7Bx-1%7D%7B6%7D%20-%5Cfrac%7Bx%2B1%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%5Cfrac%7B9-1%7D%7B6%7D%20-%5Cfrac%7B9%2B1%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%5Cfrac%7B8%7D%7B6%7D%20-%5Cfrac%7B10%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%5Cfrac%7B32%7D%7B24%7D-%20%5Cfrac%7B30%7D%7B24%7D%3D%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%5Cfrac%7B2%7D%7B24%7D%3D%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B12%7D%3D%5Cfrac%7B1%7D%7B12%7D)
This statement is correct
![15.\ \frac{1}{4}+\frac{x+1}{8}=\frac{1}{2} < ==find\ the\ common\ denominator\ (8)\\\\\frac{8}{4}+\frac{8x+1}{8}=\frac{8}{2}\\\\2+x+1=4 < ==combine\ like\ terms\\\\3+x=4 < ==subtract\ 3\ from\ both\ sides\\\\-3\ \ \ -3\\\\x=1 < ==final\ answer](https://tex.z-dn.net/?f=15.%5C%20%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7Bx%2B1%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%3C%20%3D%3Dfind%5C%20the%5C%20common%5C%20denominator%5C%20%288%29%5C%5C%5C%5C%5Cfrac%7B8%7D%7B4%7D%2B%5Cfrac%7B8x%2B1%7D%7B8%7D%3D%5Cfrac%7B8%7D%7B2%7D%5C%5C%5C%5C2%2Bx%2B1%3D4%20%3C%20%3D%3Dcombine%5C%20like%5C%20terms%5C%5C%5C%5C3%2Bx%3D4%20%3C%20%3D%3Dsubtract%5C%203%5C%20from%5C%20both%5C%20sides%5C%5C%5C%5C-3%5C%20%5C%20%5C%20-3%5C%5C%5C%5Cx%3D1%20%3C%20%3D%3Dfinal%5C%20answer)
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![\frac{1}{4}+\frac{x+1}{8}=\frac{1}{2}\\\\\frac{1}{4}+\frac{1+1}{8}=\frac{1}{2}\\\\\frac{1}{4}+\frac{2}{8}=\frac{1}{2}\\\\\frac{1}{4}+\frac{1}{4}=\frac{1}{2}\\\\\frac{2}{4}=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7Bx%2B1%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B1%2B1%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B2%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cfrac%7B2%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7D)
This statement is correct
Hope this helps!
You have to set up 2 proportions.
If the 6.9 goes with the 5 then the proportion will look like this.
6.9/5 = x/6 Cross multiply
6 * 6.9 = 5x
41.4 / 5 = x
x = 8.28 or 8.3
If on the other hand the 6.9 goes with the 6 then the second proportion is
6.9/6 = x/5
6.9 * 5 = 6X
34.5 / 6 = x
x = 5.75
Answer: D <<<<<<<<======
Answer:
No, it is smaller.
Step-by-step explanation: