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OleMash [197]
3 years ago
5

What percent of 32 is 8

Mathematics
2 answers:
arlik [135]3 years ago
5 0
25 percent of 32 is 8.\


Hope I'm the brainliest for this question!!
Svetach [21]3 years ago
4 0
0.25 OR 25%

8 divided by 32 = 0.25.
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5 Points
AnnZ [28]

Answer: 3x^4+7x^3+7x^2+11x+4

Step-by-step explanation:

(x^2+3x+4)(3x^2-2x+1)

3x^4-2x^3+x^2+9x^3-6x^2+3x+12x^2-8x+4

Collect like terms

3x^4-2x^3+9x^3+x^2-6x^2+12x^2+3x+8x+4

3x^4+7x^3+7x^2+11x+4

3 0
4 years ago
" Draw three lines with slope 2, and three lines with slope 1/3. What do you notice "
Tom [10]

Answer:

Step-by-step explanation:

1.

all the lines with slope 2 are parallel with each-other

all the lines with slope 1/3 are parallel with each-other

2.

all lines have positive slope so they go upward from left to right

3.

slope 2 is steeper then slope 1/3

4.

the distance between the parallel lines with slope (1/3) is greater for the lines with the slope 2

6 0
3 years ago
A factory bottles 511 bottles of juice in 7 minutes. Find the factory's unit rate of bottles per minute.
VashaNatasha [74]
511 divided by 7 is the unit rate. So a is how you get it but d is the answer
8 0
3 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
A company did a quality check on all the packs of nuts it manufactured. Each pack of nuts is targeted to weigh 18.25 oz. A pack
IrinaVladis [17]

Answer:

x < 17.89 or x > 18.61 , since \left | x-18.25 \right |>0.36

Step-by-step explanation:

According to the question the weight is rejected if it is more than 0.36 oz, the weight should not be beyond 0.36 oz that is from the target weight of 18.25.  

We can say that, the difference between the actual weight and the target weight is greater than 0.36 oz.

Lets say the actual weight is 'x'. So,

x-18.25>0.36

But there can be times when the actual weight 'x' could be less than 0.36, So the order will be changed:

18.25-x>0.36

The absolute value will sum up these two into a single inequality:


|x-18.25|>0.36

Simplifying the inequalities, we get:

x-18.25>0.36

x>18.61   (we have added 18.25 on both sides)


 18.25-x>0.36

Subtracting 18.25 from both the sides we get:

-x>-17.89

After sign change it is:

x

So we can see that only x < 17.89 or x>18.61 since \left | x-18.25 \right |>0.36 is the one that represents the scenario given above.

5 0
4 years ago
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