Question

32 The area of a parallelogram is (32 + sqrt(2)) square feetIf the length of the base is (4 + sqrt(2)) feet, find the height of the parallelogram in simplest radical form

Answer 1

The height of the parallelogram that has an area of (32 + √2) ft² and base of (4+√2) ft is 9(7 + 2√2) / 7 ft

How to calculate area of a parallelogram?

area of parallelogram = bh

where

• b = base
• h = height

Therefore,

area = (32 + √2) ft²

base = (4+√2) ft

Therefore,

area of a parallelogram = bh

(32 + √2) = (4+√2)h

divide both sides by (4+√2)

h = (32 + √2)  / (4+√2)

h =  (32 + √2)  / (4+√2) × (4-√2) / (4-√2)

h =  (32 + √2) (4-√2) / 16 - 4√2 + 4√2 - 2

h = 128 + 32√2 + 4√2 - 2 / 14

h = 126 + 36√2 / 14 ft

h = 18(7 + 2√2) / 14 ft

h = 9(7 + 2√2)  / 7 ft

learn more on parallelogram here: brainly.com/question/8377736