Answer:
![A=81\pi\ m^{2}](https://tex.z-dn.net/?f=A%3D81%5Cpi%5C%20m%5E%7B2%7D)
Step-by-step explanation:
Step 1
Find the radius of the circular cross section
we know that
The circumference is equal to
![C=2\pi r](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r)
we have
![C=18\pi\ m](https://tex.z-dn.net/?f=C%3D18%5Cpi%5C%20m)
substitute and solve for r
![18\pi=2\pi r](https://tex.z-dn.net/?f=18%5Cpi%3D2%5Cpi%20r)
simplify
![18=2 r](https://tex.z-dn.net/?f=18%3D2%20r)
![r=9\ m](https://tex.z-dn.net/?f=r%3D9%5C%20m)
Step 2
Find the area of the circular cross section
The area of the circle is equal to
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
we have
![r=9\ m](https://tex.z-dn.net/?f=r%3D9%5C%20m)
substitute
![A=\pi (9)^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%289%29%5E%7B2%7D)
![A=81\pi\ m^{2}](https://tex.z-dn.net/?f=A%3D81%5Cpi%5C%20m%5E%7B2%7D)
6x²-x-12
Use the foil method to multiply each term and then simplify
Answer:2 1/2 divided by 5/8 = ?
Step-by-step explanation:
The value of the expression is 25