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BabaBlast [244]
2 years ago
6

Which equation has a graph that is a parabola with a vertex at (–2, 0)?

Mathematics
1 answer:
RideAnS [48]2 years ago
4 0

Comparing to the standard equation, the parabola with a vertex at (-2,0) is given by:

y = (x + 2)²

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

In this problem, we have that h = -2 and k = 0, and all the options have leading coefficient a = 1, hence the equation is:

y = (x + 2)²

More can be learned about the equation of a parabola at brainly.com/question/17987697

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What percent of 24 is 18? 60 is what percent of 48? Write 1.052 as a percent.
ycow [4]

Answer:

24 of 18 is 75%

60 of 48 is 80%

1.052 is 105.2%

Step-by-step explanation:

4 0
3 years ago
Simplify the expression. -2 4 A. -8 B. 16 C. -16 D. 8
Sonbull [250]
The answer is -8 because -2 * 4
8 0
3 years ago
Read 2 more answers
3. I am collecting baseball cards. My goal before I turn 18 is to have 500 cards. When I tumed 10,
vladimir2022 [97]

Based on the scenario given, the equation to describe the situation will be: c + 125 + 89 = 500 and 286 cards need to be collected.

Number of cards given by grandfather = 125 cards

Number of cards that will be given by father = 89 cards

Therefore, based on the information given, the equation to describe the situation will be:

c + 125 + 89 = 500

Therefore, we can then use the equation to calculate the number of cards that need to be collected. This will be:

c + 125 + 89 = 500

c + 214 = 500

c = 500 - 214

c = 286

Therefore, the person needs to collect 286 cards.

Read related link on:

brainly.com/question/24910157

7 0
2 years ago
What is the correct answer for this equation: -7(6+8v)=6-8v​
Anuta_ua [19.1K]
The answer would be v = -1
5 0
3 years ago
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Jake rolls a six-sided die, numbered 1 to 6, five times. He rolls a 3 on two attempts.
matrenka [14]
I do believe that the answer to your question is 60%
4 0
3 years ago
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