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3 years ago

Which equation has a graph that is a parabola with a vertex at (–2, 0)?

Mathematics

1 answer:

RideAnS [48]3 years ago

4 0

Comparing to the standard equation, the parabola with a vertex at (-2,0) is given by:

y = (x + 2)²

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

In this problem, we have that h = -2 and k = 0, and all the options have leading coefficient a = 1, hence the equation is:

y = (x + 2)²

More can be learned about the equation of a parabola at brainly.com/question/17987697

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You are drawing two cards, without replacement, from a standard deck of 52 cards. What is the

Serga [27]

Answer:

Dear student,

Answer to your query is provided below

Probability of drawing a 2 at first is (4/52) = (1/13)

Probability of drawing a face card in second try without replacement = 12/51

Step-by-step explanation:

Total no. Of cards = 52

Total no. Of cards of 2 = 4

Prob. Of drawing 2 = 4/52

Total no. Of face card = 12

Total no.of cards left in deck = 51

Prob. Of drawing face card = 12/51

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3 years ago

Samantha walks a total of 2/3 mile to get to and from school each day . Find the total number of miles that Samantha walked to a

algol13

Answer:

3 1/3 miles

Step-by-step explanation:

If Samantha walks 2/3 miles everyday and they are asking for 5 days

2/3miles · 5days = 3 1/3 or 10/3 miles

4 0

3 years ago

)) Matt's bill for breakfast at a restaurant was $91. He left an 18% tip. What was the total

gladu [14]

Answer:

$107.38

Step-by-step explanation:

$91 (the price) multiplied by the percentage 18% (91 x 18 = 1630) (1638/100=16.38 [the tip})

$91 (th original price) + 15.38 (the tip) = $108.38 (final price)

4 0

3 years ago

Read 2 more answers

A spinner and 4 cards are shown below:

yan [13]

Answer: 1 over 20

Step-by-step explanation: If the spinner has 5 parts to it at purple is one of those parts then the spinner has a 1/5 chance of it landing there.

If there are 4 cards and 1 of them are pink then there is a 1/4 chance of picking pink(if done randomly)

So if we mutiply 1/4 and 1/5, we get 1/20

That is how I arrived at my answer of 1 over 20

8 0

3 years ago

Read 2 more answers

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

4 years ago