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lutik1710 [3]
2 years ago
6

A typical neutron star has a mass of about 1. 5msun and a radius of 10 kilometers

SAT
1 answer:
Triss [41]2 years ago
3 0

How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

<h3>Density of the Neutron star</h3>

Density

ρ = m / V

Where:

ρ= density

m = mass of the planet 5.98 10²⁴ km

V =volume of the spherical layer

Volume of a sphere

Volume = 4/3 π r³

Mass = 1.5 = 1.5 1,991 10³⁰

Mass= 2.99 10³⁰ kg

Density:

ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]

ρ is = 7.13 10 17 kg / m³

V = 5.98 10²⁴ / 7.13 10¹⁷

V = 8,387 10⁶ m³

Thickness of the layer

V = 4π r² e

e = V / 4π r

e = 8,387 10⁶ / [4π (10 10³)²]

e = 6.67 10⁻³ m

Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

Learn more about Density of the Neutron star here:brainly.com/question/15700804

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At an ocean depth of 20 meters, a buoy bobs up and then down 2 meters from the ocean's depth. Four seconds pass from the time th
stiv31 [10]

The first and second coordinate points of the sine graph are;

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<h3>Sine Graph expression</h3>

The general formula we will use to plot the graph is;

y = [Asin (2πx/t)] + ∅      (Note that sin is in radians)

where;

A is amplitude

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We are told that the buoy bobs up and then down 2 meters from the ocean's depth. This means that;

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Since the second point must be a maximum or minimum value on the graph closest to the first point, then we put 2 for x to get the coordinate of the second point;

y = [2sin((2π*2/8)] + 20  

y = [2sin((2π*2/8)] + 20  

y = [2sin(π/2)] + 20  

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Using the first and second point coordinates, we will use sine tool to graph the function as attached below.

Read more about sine graph at; brainly.com/question/18055768

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hope this helps.
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