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1 year ago

A typical neutron star has a mass of about 1. 5msun and a radius of 10 kilometers

SAT

1 answer:

Triss [41]1 year ago

3 0

How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

<h3>Density of the Neutron star</h3>

Density

ρ = m / V

Where:

ρ= density

m = mass of the planet 5.98 10²⁴ km

V =volume of the spherical layer

Volume of a sphere

Volume = 4/3 π r³

Mass = 1.5 = 1.5 1,991 10³⁰

Mass= 2.99 10³⁰ kg

Density:

ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]

ρ is = 7.13 10 17 kg / m³

V = 5.98 10²⁴ / 7.13 10¹⁷

V = 8,387 10⁶ m³

Thickness of the layer

V = 4π r² e

e = V / 4π r

e = 8,387 10⁶ / [4π (10 10³)²]

e = 6.67 10⁻³ m

Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

Learn more about Density of the Neutron star here:brainly.com/question/15700804

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Find δs o for the combustion of methane to carbon dioxide and liquid water.

mote1985 [20]

The entropy change ΔS for the combustion of methane to carbon dioxide and liquid water is -242.6 J/mol.K

<h3>What is the Entropy in a Chemical system?</h3>

In a chemical system, Entropy (ΔS) is a quantitative measure of the variety of possible ways to disperse energy inside a chemical system.

In an isothermal process, entropy is determined as the quantity of heat transmitted to a system.

The chemical reaction for the combustion of methane can be expressed as:

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The standard entropy of the combustion is expressed as:

$\mathbf{\Delta S^0 =(S^0 _{CO_{2}} + 2 \times S^0 _{H_{2}O} )+(-S^0 _{CH_{4}} -2 \times S^0 _{O_{2}} })$

Replacing the standard entropies of the compounds into the above equation, we have:

$\mathbf{\Delta S^0 =(213.8 \8 \ J/mol.K + 2 \times69.92 \ J/mol.K )+(-186.16 \ J/mol.K -2 \times 205.04 \ J/mol.K})$

$\mathbf{\Delta S^0 =-242.6 \ J/mol.K}$

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