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Doss [256]
2 years ago
5

What important decisions did the characters make in the story “Relationship” by Jhoanna Lynn Cruz

SAT
1 answer:
Rainbow [258]2 years ago
3 0

Answer:

Sapay Koma” is a story where we can see that love do exist, and where all relationship had a story to tell. As I reflect, I realize that love is about sacrificing, it is all about decision-making. That decision should fit for all, that everyone should benefits the good result of it. But most important is, we should care for our self, we must follow what our heart and mind speaks. Instead of thinking to give up, let’s fight the things that is worth fighting for; and that thing is what we call “LOVE”.

Impossible can be Possible, that’s what love can do. Sometimes because of this we can even sacrificed all what we have in life, all that we treasured most. We always tend to do everything that is impossible for us to do and even the hardest thing that we never ever made from the rest of our life, that is the power of Love. Nothing is impossible in Love!

Explanation:

Hope it helps :)

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A football team won 60% of the total games it played during the year. If it lost 30 games in all and no games were tied, find th
sineoko [7]

Answer: 75 games.

Explanation:

60% - ?

40% - 30 games

20% = 15 games

20% x 3 = 60%

15 x 3 = 45 games

40% + 60% = 100%

30 + 45 = 75 games

The total number of games would be 75! Hope that helps.

7 0
2 years ago
How to make slime strecthy
joja [24]
Add borax
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4 0
3 years ago
Read 2 more answers
All forms of electromagnetic radiation occur as waves.<br> true<br> false
Liula [17]
I believe it is false.
I think that electromagnetic radiation can occur in other forms such as rays. Rays and waves seem similar and are both apart of the electromagnetic spectrum, but they take different forms.
5 0
2 years ago
Which of the following is a difference between phase i and phase ii of meiosis?(1 point).
Serjik [45]

AnswerHowever, Meiosis I begins with one diploid parent cell and ends with two haploid daughter cells, halving the number of chromosomes in each cell. Meiosis II starts with two haploid parent cells and ends with four haploid daughter cells, maintaining the number of chromosomes in each cell.:

Explanation:

3 0
2 years ago
A survey participant is randomly selected. Let f be the event that the participant’s first motor vehicle had four cylinders and
andreev551 [17]

The value of P(fc and u) is 0.09

From the complete question, we have the following highlights:

  • A total of 200 participants were surveyed.
  • 18 of the survey participant's first motor vehicle had four cylinders and the participant’s first motor vehicle was an SUV.

These mean that;

n(fc\ and\ u) = 18

n =200

So, the value of P(fc and u) is calculated using:

P(fc\ and\ u) =\frac{n(fc\ and\ u)}{n}

This gives

P(fc\ and\ u) =\frac{18}{200}

Divide 118 by 200

P(fc\ and\ u) =0.09

Hence, the value of P(fc and u) is 0.09

Read more about probabilities at:

brainly.com/question/8652467

5 0
2 years ago
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