Area of Circle=


=

x

= 490.87

Area of Oven tray= 60cm x 50cm
= 3000

: . # tin that can hold on bake tray= 3000

/ <span>490.87

= 6.11
Thus making it logically 6..... </span>
The random probability of event X, wheel stopping on a white slice is 0.9 while the probability of not X, wheel stopping on Grey slice is 0.1
- Total numbers on wheel = total possible outcomes = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
- Grey colored portion = {3}
- White colored portion = {1, 2, 4, 5, 6, 7, 8, 9, 10}
- X = Event that wheel stops on a white slice
- P(X) = number of white slices ÷ total number of slices
Therefore, the probability that wheel stops on a white slice is 0.9 while, the probability that wheel does not stop on a white slice is 0.1
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Answer:225 jeans.
Step-by-step explanation: What we need to do here is convert the number of jeans to a percentage. There were 25 jeans when 50 customers were surveyed and 25 is half of 50 or 50%. This means that if 450 pairs of pants are ordered half of them should be jeans. 450/2 = 225.
The inequality is 8-1/4x>27. The solution of the inequality is b<-76.
Given that,
The inequality is 8-1/4x>27
We must determine how to address the inequity.
Take,
8-1/4x>27
Multiply the inequality's two sides by its lowest common denominator,
4×8-4×1/4b>27×4
Reduce the expression to the lowers term,
4×8-b>4×27
Calculate the product or quotient,
32-b>4×27
Calculate the product or quotient,
32-b>108
Rearrange unknown terms to the left side of the equation,
-b>108-32
Calculate the sum or difference,
-b>76
Divide the inequality's two sides by the variable's coefficient,
b<-76
Therefore, the solution of the inequality is b<-76.
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Answer:
C. both student 1 and student 2
Step-by-step explanation:
Dilation does not change any angles, so the triangles are similar and the trig functions of corresponding angles will be identical.
The slope of CB is -1/3 and the slope of BA is 3, so they multiply together to give -1. That means the segments are at right angles and the triangle is a right triangle.
Both the premise and the conclusion of each student is correct.