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Andreas93 [3]
2 years ago
5

A user generates printouts consisting of several pages of seemingly random characters every time he prints to a network printer.

The printer seems to work fine for all other users. What is the most likely cause of the problem
Computers and Technology
1 answer:
Aleksandr [31]2 years ago
4 0

Answer:

The printer driver is incorrectly installed by the user.

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Why is the Microsoft website considered the best source for information about pagefile.sys?​
Bumek [7]

Answer:

uyjhjyr

Explanation:

yjdhtgjyhstjsytjuttjyh

6 0
2 years ago
Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex:
ArbitrLikvidat [17]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 

 System.out.print("Enter a number: ");

 int userVal = input.nextInt();

 

 String aString;

 if(userVal < 0)

     aString = "negative";

 else

     aString = "non-negative";

     

 System.out.println(aString);

}

}

Explanation:

Ask the user to enter a number and set it to userVal

Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"

Print the string

8 0
3 years ago
If there are 8 opcodes and 10 registers, a. What is the minimum number of bits required to represent the OPCODE? b. What is the
Nimfa-mama [501]

Answer:  

For 32 bits Instruction Format:

OPCODE   DR               SR1                   SR2      Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE  

     = 12 + 3 = 15  

Total  number of bits for instruction format = 32  

Maximum  No. of Unused bits = 32 – 15 = 17 bits  

OPCODE                DR              SR1             SR2              Unused bits

  3 bits              4 bits          4 bits           4 bits                17 bits

7 0
3 years ago
Choose the types of education an ISS professional
Viefleur [7K]

Answer:

It's A. a CompTIA certificate and D. a Microsoft-certified desktop support

certificate

Explanation:

I got it right.

7 0
3 years ago
What is the memory of a computer called
Nataliya [291]
It is called Ram in another term for memory :)
6 0
3 years ago
Read 2 more answers
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