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Lady bird [3.3K]
3 years ago
10

If you plan on operating several applications at s time, the amount of RAM should be considered when purchasing a computer

Computers and Technology
2 answers:
Taya2010 [7]3 years ago
7 0

Answer:

True

Explanation:

Hi, the statement is true.

Ram (Random access memory) is used to store active data from active applications and system processes.

If a computer has more RAM, it can run more applications at the same time without slowing significantly the system down.

Today’s standard is 8 gigabytes of ram.

Feel free to ask for more if needed or if you did not understand something.

olchik [2.2K]3 years ago
5 0
True, if you plan on running a lot of applications at the same time, you should get more RAM for your computer. 8+ GB of DDR4 ram should be good for every day applications. 16GB should be more than enough for everything for the next couple years.
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If there are 8 opcodes and 10 registers, a. What is the minimum number of bits required to represent the OPCODE? b. What is the
Nimfa-mama [501]

Answer:  

For 32 bits Instruction Format:

OPCODE   DR               SR1                   SR2      Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE  

     = 12 + 3 = 15  

Total  number of bits for instruction format = 32  

Maximum  No. of Unused bits = 32 – 15 = 17 bits  

OPCODE                DR              SR1             SR2              Unused bits

  3 bits              4 bits          4 bits           4 bits                17 bits

7 0
3 years ago
Drag each label to the correct location on the image.
andrezito [222]

Answer:

1.) Relative cell reference - A1

2.) Absolute cell reference - $D$2

3.) Mixed cel reference - $D2

Explanation:

In Microsoft Excel, cell references are very important and critical when dealing with formula. They can give you what you’re looking for or make your entire worksheet incorrect.

A cell reference is a cell address or a range of cell addresses that can be used in a formula.

There are three types of cell references and they are;

a) Relative reference

b) Absolute reference

c) Mixed reference

A relative cell reference is a cell reference that changes when you copy the formula to other cells. It s usually just a normal cell reference like A1, B2, C3. If a formula with a relative cell reference is copied down to other cells, the formula will change. That is a formula with a relative cell reference changes with respect to the cell which it is copied to.

An absolute reference does not change when you copy the formula to other cells. In absolute references, the dollar sign $ is used to “lock” both the row and column so that it does not change when it is copied to other cells. An example is $D$2.

Using a mixed cell reference, one is trying to see that only either the row or column changes with respect to other cells when they are copied. It is like “locking” either the column or the row while changing the other. Just like from the example, $D2 is a mixed cell reference where only the column is locked such that only the row changes when the formula is copied to other cells.

7 0
3 years ago
In this lab, you will build a system for package delivery services that provides different shipping options with specific price.
Alex73 [517]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace st d;

class Package

{

protected:

//sender properities

char sname[10],saddress[50],scity[20],sstate[20];

long int szip;

//Receiver properities

char rname[10],raddress[50],rcity[20],rstate[20];

long int rzip;

//additonal datamembers

float weight,cost;

public:

Package() //Default constructor

{

strcpy(sname,"");strcpy(saddress,"");strcpy(scity,"");

strcpy(sstate,"");szip=0;

strcpy(rname,"");strcpy(raddress,"");strcpy(rcity,"");

strcpy(rstate,"");rzip=0;

weight=cost=0;

}

Package(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c) //Constructor with parameter

{

strcpy(sname,sn);strcpy(saddress,sa);strcpy(scity,sc); //copying each parameter value to data member

strcpy(sstate,ss);szip=0;

strcpy(rname,rn);strcpy(raddress,ra);strcpy(rcity,rc);

strcpy(rstate,rs);rzip=0;

weight=w;cost=c;

}

float calculateCost() //calculating cost

{

return weight*cost;

}

};

class TwoDayPackage:public Package //Inheritance

{

float flatfee;

public:

TwoDayPackage(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c,float ff) //Constructor with parameter

{

Package(sn,sa,sc,ss,sz,rn,ra,rc,rs,rz,w,c); //calling super class constructor

flatfee=ff; //copy last parameter

}

float calculateCost() //redefined calculateCost function

{

return (weight*cost)+flatfee; //return total cost

}

};

class OverNightPackage:public Package //Inheritance

{

float addfee;

public:

OverNightPackage(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c,float a f) //constructor with parameter

{

Package(sn,sa,sc,ss,sz,rn,ra,rc,rs,rz,w,c); //calling super class constructor

addfee=a f; //copy last parameter

}

float calculateCost() //redefined calculateCost function

{

return (weight*cost)+addfee; //calculating total cost

}

};

int main()

{

Package package1("lou brown","1 main st","boston","ma",11111,"mary smith","7 elm st","new york","ny",22222,8.5,0.5); //creating objects

TwoDayPackage package2("lisa klein", "5 broadway", "somerville", "ma", 33333, "bob george", "21 pine rd", "cambridge", "ma", 44444, 10.5, .65, 2.0 );

OverNightPackage package3 ("ed lewis", "2 oak st", "boston", "ma", 55555, "don kelly", "9 main st", "denver", "co", 66666, 12.25, .7, .25 );

cout<<"\nPackage Cost : "<<package1.calculateCost(); //calling each cost

cout<<"\nTwoDay Package Cost : "<<package2.calculateCost();

cout<<"\nOvernight Package Cost : "<<package3.calculateCost();

return 0;

}

8 0
3 years ago
Programming in https<br>​
kakasveta [241]
What?? explain your question
3 0
2 years ago
The read/write heads of a hard disk gently rest on the hard disk platters in order to read and write the data.
noname [10]
The answer is FALSE because the interior of commercial Hard disk drive is with stack of magnetic disks (platters) containing the user’s data and a rotating arm supporting the magnetic heads. The rotating arm is moved by the torque generated by a voice coil motor (VCM) mounted at one end of the arm. Data read/write operations rely on the capability of the governing unit of the HDD to maintain the magnetic read/write heads as close as possible to center of the desired track. Typically, reliability of data reading and writing is guaranteed when the head is kept within 5% of the track pitch from the track center. This means that the accuracy required for the head positioning is in the range of a few tens of nanometers.
6 0
3 years ago
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