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4 years ago

If you plan on operating several applications at s time, the amount of RAM should be considered when purchasing a computer

Computers and Technology

2 answers:

Taya2010 [7]4 years ago

7 0

Answer:

True

Explanation:

Hi, the statement is true.

Ram (Random access memory) is used to store active data from active applications and system processes.

If a computer has more RAM, it can run more applications at the same time without slowing significantly the system down.

Today’s standard is 8 gigabytes of ram.

Feel free to ask for more if needed or if you did not understand something.

olchik [2.2K]4 years ago

5 0

True, if you plan on running a lot of applications at the same time, you should get more RAM for your computer. 8+ GB of DDR4 ram should be good for every day applications. 16GB should be more than enough for everything for the next couple years.

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Intellectual ______ is the legal term for ownership of intangible assets such as ideas, art, music, movies, and software.

77julia77 [94]

Answer:

Property

Explanation:

Intellectual Property (IP) is the lawful protection of human idea/intellect by unauthorised users. These human intellects are intangible assets that have both moral and commercial value. They include ideas, art, music, movies, software e.t.c.

Common types of Intellectual property include

Copyrights
patents
Trade Marks
Trade Secrets

6 0

3 years ago

Read 2 more answers

For a list of numbers entered by the user and terminated by 0, find the sum of the positive number and the sum of the negative n

Katena32 [7]

Summarize all positive numbers as follows: + It's good. The total of all negative numbers is:, write it down. + Unfavorable.

<h3>What is C++ language?</h3>

C++ language is defined as a general-purpose programming language that supports procedural, object-oriented, and generic programming and is case-sensitive and free-form. As well as being used for in-game programming, software engineering, data structures, and other things, C++ is also utilized to create browsers, operating systems, and applications.

An application that adds all positive integers and stores them in variables, as well as adding all negative numbers and storing them in variables. The software should print the values for both variables at the conclusion and compute their average. When the user enters a zero, the software should terminate.

Thus, summarize all positive numbers as follows: + It's good. The total of all negative numbers is:, write it down. + Unfavorable.

To learn more about C++ language, refer to the link below:

brainly.com/question/1516497

#SPJ1

8 0

1 year ago

I’m failing this class and i’m stuck on this one, this is the code from the last lesson:

serg [7]

lst=([])

def avgGPA(lst1):

total = 0

count = 0

for x in lst:

if type(x) == int:

total += x

count += 1

return total/count

def GPAcalc(grade, weighted):

grade = grade.lower()

dictionary = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}

if weighted == 1 and grade in dictionary:

lst.append(dictionary[grade]+1)

return "Your GPA score is: " + str(dictionary[grade] + 1)

elif weighted == 0 and grade in dictionary:

lst.append(dictionary[grade])

return "Your GPA score is: " + str(dictionary[grade])

else:

lst.append("Invalid")

return "Invalid"

classes = int(input("How many Classes are you taking? "))

i = 0

while i < classes:

print(GPAcalc(input("Enter your Letter Grade: "), int(input("Is it weighted? (1 = yes) "))))

i += 1

print("Your weighted GPA is a "+str(avgGPA(lst)))

If you need me to change any code, I'll do my best. I hope this helps!

6 0

3 years ago

In object oriented programming, what is another name for the "attributes" of an object?

Ket [755]

I believe the word you're looking for is properties.

7 0

3 years ago

A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca

natima [27]

Answer:

There are 5,598,527,220 ways to choose 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 from a set of 13 cards.

Explanation:

The crucial point of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of combination since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for combinations is $\\ \frac{n!}{(n-k)!k!}$ , where n is the total of elements available and k is the size of a selection of k elements from which we can choose from the total n.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

$\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287$ , since $\\ \frac{8!}{8!} = 1$ .

Choosing 4 cards of type 2 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715$ , since $\\ \frac{9!}{9!} = 1$ .

Choosing 2 cards of type 3 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78$ , since $\\ \frac{11!}{11!}=1$ .

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78$ .

We still need to make use of the Multiplication Principle to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the multiplication of all them.

5 0

3 years ago