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3 years ago

Which graph represents the same relation as the rule y = 2x, for all real numbers x?

Mathematics

1 answer:

Feliz [49]3 years ago

4 0

Answer:

C is your answer...

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T/15=3 what operation is that?

stich3 [128]

Answer:

t = 45

Step-by-step explanation:

$\frac{t}{15} = \frac{3}{1}$

t × 1 = 15 × 3

t = 45

5 0

3 years ago

Rico wants to find the distance between the points (-2,-3) and (2,-5) his work is shown.|-3| + |-5| = 3+5 = 8the distance is 8 u

tino4ka555 [31]

Answer:

Riko is wrong

Step-by-step explanation:

To find the distance of two point, we use the following formula:

A (x1, y1)

B (x1, y2)

AB = $\sqrt{(x2-x1)^{2} + (y2-y1)^{2} }$

In this situation, we have:

A (-2,-3)

B (2,-5)

So the distance is: $\sqrt{(2 - (-2))^{2} + (-5 - (-3))^{2} }$ = $\sqrt{4^{2} + 8^{2} }$ = $\sqrt{80} = 4\sqrt{5}$

Hope it will find you well.

5 0

3 years ago

Read 2 more answers

Helpppp please

Doss [256]

Answer:

Pppppppppppppppppppppppppp

6 0

3 years ago

Please answer this question now

LUCKY_DIMON [66]

The answer is 72°
the m112°-40°= 72°

6 0

4 years ago

Will Mark Brainlest helpppp

Anvisha [2.4K]

Answer:

R = $\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]$

Step-by-step explanation:

P - Q + R = I ( I is the identity matrix )

$\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right]$ - $\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right]$ + R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$ ( subtract corresponding elements )

$\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right]$ + R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$

$\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]$ + R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$

R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$ - $\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]$

6 0

3 years ago