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3 years ago

In a plane if two line are perpendicular to the same line then they ___ to each other.

Mathematics

2 answers:

Kruka [31]3 years ago

6 0

It’s either skew parallel

Debora [2.8K]3 years ago

4 0

Answer:

parallel

Step-by-step explanation:

Two lines perpendicular to the same line must be parallel to each other.

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Helen has 4 jogging outfits and three pairs of shoes. How many different outfits can she make?

Afina-wow [57]

She can make 12 different outfits

4 0

4 years ago

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Find the measure of 14x+7+44+9x+3=180?

IRISSAK [1]

Answer:

X = 40

Step-by-step explanation:

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3 years ago

Chris wanted to transform the graph of the parent function Y= cot (x) by horizontally compressing it so that it has a period of

pashok25 [27]

Answer:

He didn't calculate the b-value correctly.

Step-by-step explanation:

The given parent function is:

$y = \cot(x)$

The transformation is of the form:

$y =a \cot(bx + c) + d$

The period is given by

$\frac{\pi}{b}$

If we want the new function to have a period of

$\frac{2}{\pi}$

Then we solve the following equation for b.

$\frac{\pi}{b} = \frac{2}{\pi}$

$b = \frac{ {\pi}^{2} }{2}$

$- \frac{c}{b}$

will translate the graph horizontally to the right by

$\frac{c}{b}$

units.

+d shifts the graph up by d units.

The new function then becomes:

$y = \cot( \frac{ {\pi}^{2} }{2} (x - \frac{\pi}{4} ) )+1$

3 0

3 years ago

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Find the equation of the linear function represented by the table below in slope-intercept form.

Anit [1.1K]

Answer:

es x positivo por qué y es negativo

Step-by-step explanation:

me entendiste

3 0

3 years ago

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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

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3 years ago

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