Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
Answer:
it just takes longer
Step-by-step explanation:
you count by 1 from 100 until 1000
Answer:
To find the answer we only need to know,
Total no.of girls and Total no.of right handed girls.
So,
Total no.of right handed girls = 7/8
Total no.of girls = 8/8 (as given in question)
Total no.of left handed girls is,
(Fraction of total no.of girls) - (Fraction of total no.of left handed girls)
= 8/8 - 7/8
= 1/8
∴ 1/8 of the girls in the school are left handed.
-1+5x
You combine like terms:
Here there are two different ones.
the number without the variable (the 1s) and the one with the variable (5x)
All you have to do is combine them:
1+(-1)+(-1) = 1-1-1 = -1
5x = 5x
So, the answer would be -1+5x
Hope this helps :D
4c6d3 x 3c4d
4 x 3=12
12c
you add the powers so 6+4=10
12c10
d3 x d=d3
12c10d3
that is the answer i think
