Answer:
On 5th day and 13th day Attendance was equal for both plays and it was
231 for each .
Step-by-step explanation:
In order to find same attendance ,we need plug both equation equal
-x^2+26x+126 = 8x+191
-x^2+26x-8x+126-191 = 0
-x^2 +18x-65 =0
multiplying both sides by -1 ,we get
x^2 -18x+ 65 =0
(x-5) (x-13) =0
x =5 and x =13
On 5th day and 13th day attendance was same.
And attendance can be obtained by plugging x =5 in either of equation
y = 8(5)+191
= 40 +191
= 231
The answer is 8x.
You are combining like terms as 5 and 3 both have x so you are simply adding 5+3= 8
After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers. Find the LCM of these sets of numbers. Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3's, and 21 has one 7, so we multiply 3 two times, and 7 once.
A) No one in the class studied more then 5 hours
