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3 years ago

9

Express 3/8 as a decimal

2 answers:

Softa [21]3 years ago

6 0

Answer: 0.375

Step-by-step explanation: To get this you would have to divide 8 with 3 like you would with a regular fraction

slavikrds [6]3 years ago

6 0

3/8 can be expressed as 0.375 in a decimal.

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Please help I will mark brainlest

spin [16.1K]

Hope this helps, pls mark me brainliest

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3 years ago

Given the height, h, and the volume v of a certain cylinder, alex uses the formula v ph r 5 !§ to compute its radius, r, to be 1

dmitriy555 [2]

We know that
volume of a cylinder=pi*r²*h
r=√[V/(pi*h)]
r=10 m

A <span>second cylinder has
V2=V-----> volume of the second cylinder
h2=25*h----> height of the second cylinder
r2----> radius of the second cylinder
r2=</span>√[V2/(pi*h2)]----> r2=√[V/(pi*25*h)]---> r2=(1/5)*√[V/(pi*h)

r2=(1/5)*10-----> r2=2 m

the answer is
<span>the radius of the second cylinder is 2 m</span>

7 0

3 years ago

3(x - 2) + 48 = -3x

kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

3x - 6 + 48 = -3x ➡ -6 + 48 = -6x ➡ 42 = -6x ➡ -7 = x

As shown, the answer is x=-7.

8 0

3 years ago

What is the solution to x^6 – 6x ^5 + 15x ^4 – 20x ^3 + 15x^ 2 – 6x + 1 ≥ 0? x = 0 x = 1 all real numbers all real numbers excep

g100num [7]

Answer:

Answer: C all real numbers

8 0

2 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago