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Katarina [22]
2 years ago
7

What is the scale factor? Multiple choice

Mathematics
1 answer:
kap26 [50]2 years ago
7 0

Answer:

  • 0.75
  • 3/4
  • post/pre

Step-by-step explanation:

In general, a scale factor is applied to an original (pre) to obtain an image (post). It is the ratio post/pre that expresses the relationship between image dimensions and original dimensions.

Here, that post/pre ratio is 3/4 = 0.75.

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Write the number 0.00003852 in standard form.
Basile [38]

Answer: 3.852

Step-by-step explanation:give me brianlest

4 0
2 years ago
Compare: 7/20 O 35%<br><br> who answers first get brainlest
Ugo [173]

Step-by-step explanation:

7/20

=0.35

35%

=35/100

=0.35

Hence, 7/20=35%

7 0
3 years ago
I need help fast please I don’t understand this and I’ve been struggling for a while. Can I get a brain list please or a tutor t
solong [7]

Answer:

4 √6

Step-by-step explanation:

We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:

m²+z² = (8+4)² = 12²

4²+n²=z²

8²+n²=m²

We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.

4²+n²=z²

subtract 4²=16 from both sides

z²-16 = n²

plug that into the third equation

64 + z² - 16 = m²

48 + z² = m²

subtract 48 from both sides to solve for z²

z² = m² - 48

plug that into the first equation

m² + m² - 48 = 144

2m² - 48 = 144

add 48 to both sides to isolate the m² and its coefficient

192 = 2m²

divide both sides by 2 to isolate the m²

96 = m²

square root both sides to solve for m

√96 = m

we know that 96 = 16 * 6, and 16 = 4², so

m = √96 = √(4²*6) = 4 √6

5 0
2 years ago
What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2 + 3x^2y^2 + 3x^4y?
WINSTONCH [101]

Given:

The polynomials are:

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

To find:

The completely simplified sum of the polynomials.

Solution:

We have,

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

The sum of given polynomials is:

Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y

Sum=-2xy^5+3x^4y+3x^2y^2

Therefore, the sum of the given polynomials is -2xy^5+3x^4y+3x^2y^2. It is a polynomial with degree 6 and leading coefficient -2.

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3 years ago
Who here play fort nite and rocket leauge
Wewaii [24]

Answer:

I play fort nite i never like rocket

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