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3 years ago

I need help on these questions please?

Mathematics

1 answer:

nadezda [96]3 years ago

8 0

Answer:

x/25 = 7/2 --> x = 25 * 7/2 = 87.5 miles

x = 45/75 = 0.6 = 60%

x = 1/(1/24 + 1/30) = 13 1/3 minutes

x/2 + x/6 = 12 --> x = 18

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-5x-18y=-28 and -10x+9y=-11 solve elimination

Dmitry [639]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=1$

Step-by-step explanation:

Given the equations

$-5x-18y=-28$

$-10x+9y=-11$

solving the system of the equation by elimination method

$\begin{bmatrix}-5x-18y=-28\\ -10x+9y=-11\end{bmatrix}$

$\mathrm{Multiply\:}-5x-18y=-28\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-10x-36y=-56$

$\begin{bmatrix}-10x-36y=-56\\ -10x+9y=-11\end{bmatrix}$

$-10x+9y=-11$

$-$

$\underline{-10x-36y=-56}$

$45y=45$

$\begin{bmatrix}-10x-36y=-56\\ 45y=45\end{bmatrix}$

solve 45y=5 for y:

$45y=45$

$\frac{45y}{45}=\frac{45}{45}$

$y=1$

$\mathrm{For\:}-10x-36y=-56\mathrm{\:plug\:in\:}y=1$

solve $-10x-36\cdot \:1=-56$ for x:

$-10x-36\cdot \:1=-56$

$-10x-36=-56$

Add 36 to both sides

$-10x-36+36=-56+36$

$-10x=-20$

$\frac{-10x}{-10}=\frac{-20}{-10}$

$x=2$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=1$

5 0

3 years ago

You have prizes to ren

Agata [3.3K]

Answer:

$475.00

Step-by-step explanation:

Subtract $822.00 and $347.00 then you'll get $475.00

7 0

3 years ago

If the perimeter of a square is 4x - 24, what is the<br> area of the square?

DedPeter [7]

Answer:

A = (x - 6)² sq. units or

A = (x² - 12x + 36) sq. units

Step-by-step explanation:

P = 4s, where s is the side.

4s = 4x - 24

s = x - 6

A = s²

A = (x - 6)² sq. units or

A = (x² - 12x + 36) sq. units

7 0

3 years ago

8oz./1 cup = ?/12 cups. How many ounces are in 12 cups?

IRISSAK [1]

Answer:

12cups=96oz.

Step-by-step explanation:

multiply the volume value by 8

12 oz equals 1.50 cups. 1 ounce is equivalent to 0.125 cups, and there are 1.50 cups in 12 ounces.

4 0

3 years ago

Read 2 more answers

Suppose that we have a sample space S5 {E1, E2, E3, E4E4E, E5, E6, E7}, where E1, E2, . . ., E7 denote the sample points. The fo

VashaNatasha [74]

Answer:

P(A) = 0.4 ; P(B) = 0.50 ; P(C) = 0.60 ; P(A u B) = 0.65 ; P(A n B) = 0.25 ;

A and C are mutually exclusive ;

0.5

Step-by-step explanation:

S = {E1, E2, E3, E4, E5, E6, E7}

P(E1) = .05, P(E2) = .20, P(E3) = .20, P(E4) = .25, P(E5) = .15, P(E6) = .10, and P(E7) = .05

Let:

A{E1,E4,E6}

B{E2,E4,E7}

C{E2,E3,E5,E7}

P(A) = 0.05 + 0.25 + 0.10 = 0.40

P(B) = 0.20 + 0.25 + 0.05 = 0.50

P(C) = 0.20 + 0.20 + 0.15 + 0.05 = 0.60

AUB = {E1, E2, E4, E6, E7}

P(A u B) = 0.05 + 0.20 + 0.25 + 0.10 + 0.05 = 0.65

AnB = {E4}

P(A n B) = 0.25

A and C are mutually exclusive if AnC = ∅

A n C = ∅

Hence, A and C are mutually exclusive.

B complement = B' = {E1, E3, E5, E6}

P(B') = 0.05 + 0.20 + 0.15 + 0.10 = 0.5

5 0

3 years ago