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Aleks [24]
3 years ago
5

What is 862-419 estimated to

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0

Answer: 443

Step-by-step explanation:

Afina-wow [57]3 years ago
6 0
Estimated to 440 but, the correct answer is 443
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What is the product of a+3 and −2a2+15a+6b2?
Arte-miy333 [17]

Answer:

<h3>            -2a³ + 9a² + 6ab² + 45a + 18b² </h3>

Step-by-step explanation:

(a + 3)×(−2a² + 15a + 6b²) =

= a×(−2a² + 15a + 6b²) + 3×(−2a² + 15a + 6b²) =

= -2a³ + <u>15a²</u> + 6ab² - <u>6a²</u> + 45a + 18b² =

= -2a³ + 9a² + 6ab² + 45a + 18b²

8 0
2 years ago
Read 2 more answers
There are 5.32 of face paint in each paint pot she used 13 of them while painting forces how many milliliter of face paint
Goshia [24]

Answer:

69.16

Step-by-step explanation:

5 0
2 years ago
What are the solutions to the equation y2 – 1 = 48?
Furkat [3]

{y}^{2}  - 1 = 48 \\  {y}^{2}  = 49 \\ y =  \sqrt{49}  \\ y =  - 7 \: or \: 7

{y}^{2}  - 1 = 24 \\  {y}^{2}  = 25 \\ y =  \sqrt{25}  \\ y =  - 5 \: or \: 5

Hope this helps. - M
6 0
3 years ago
Explain how you can find the value of the expression -5+12+10-7
Oliga [24]
-- Take. -5 . -- Add 12. to it. -- To the result, add 10. --- From that result, subtract 7 . -- The current result is the value of the expression.
5 0
3 years ago
Read 2 more answers
Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, space, c, m. He wanted his balloon to be
jonny [76]
The original volume of the balloon is given by:
 V1 = (4/3) * (pi) * (r ^ 3)
 Where,
 r: radius of the sphere.
 Substituting values:
 V1 = (4/3) * (pi) * (1 ^ 3)
 V1 = (4/3) * (pi) * (1)
 Then, the volume of the current sphere is:
 V2 = (4/3) * (pi) * ((1 + 2 * (1)) ^ 3)
 V2 = (4/3) * (pi) * ((1 + 2) ^ 3)
 V2 = (4/3) * (pi) * ((3) ^ 3)
 V2 = (4/3) * (pi) * (27)
 The relation of volumes is:
 V2 / V1 = ((4/3) * (pi) * (27)) / ((4/3) * (pi) * (1))
 V2 / V1 = 27/1
 Answer:
 
The ratio of the current volume of the balloon to the original volume of the balloon is:
 
27: 1
6 0
3 years ago
Read 2 more answers
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